Question

我正在尝试使用python做一个请求。 API使用：

curl -X POST --header 'Content-Type: application/json' --header 'Accept: application/json' -d '{ \ 
   "$class": "org.acme.model.sensor", \ 
   "sensorId": "1", \ 
   "type": "Temperature", \ 
   "value": "10", \ 
   "timestamp": 1234123 \ 
 }' 'http://localhost:3000/api/sensor'

创建一个新的传感器。我试图用python做它，我创建了概念证明：

data = {
    "$class": "org.acme.model.sensor",
    "sensorId": "",  #change in the loop with i
    "type": "Temperature",
    "value": "10",
    "timestamp": 382453824
}

header = {
    "Content-Type" : "application/json",
    "Accept":"application/json"
}

url = "http://localhost:3000/api/sensor"
for i in range(2):
    data["sensorId"]=str(i+1)
    response = requests.post(url, data=data, headers=header)

    #Now I modify the data
    data["Temperature"]="50"
    response = requests.put(url, data=data, headers=header)

现在，为了擦除：

for i in range(2):
    url="http://localhost:3000/api/sensor/"+str(i+1)
    response = requests.delete(url)

使用curl，它可以正常工作但不能使用python代码。它甚至无法创建对象。

Answer 1

import requests
import json

header = {
"Content-Type" : "application/json",
"Accept":"application/json"
}

您需要使用json.dumps将字典转换为正确的格式，并且需要使用request.post代替delete

request_url = 'YOUR_END_POINT'
data = json.dumps(data)
response = requests.post(url=request_url,data=data,headers=headers)

我认为应该解决它。

使用python的API请求

1 个答案: