Question

我已将此文件存储在DATETIME类型的数据库中考虑它的价值： 2017-12-14 16:17:21

这是我的程序逻辑。我想检查是否过了72小时其他回声你需要等待48小时22分55秒。例如。

$row = $res->fetch_assoc();
$last_dl = $row['last_dl'];

// To seconds from 1970
$last_dl = strtotime($last_dl); //120
$seventy_two_hours_in_seconds = 60 * 60 * 72;

if (time() > ($last_dl + $seventy_two_hours_in_seconds)) {
    echo "72 Passed";
} else {
    echo "You need to wait: " . date('H/h i/m s/s',mktime(0, 0, ($last_dl + $seventy_two_hours_in_seconds) - time()));
}

逻辑有什么问题。因为它显示出更少的时间。

Answer 1

您可以计算等待的秒数，以及以小时，分钟和秒为单位的时间：

<?php
$row = $res->fetch_assoc();
$last_dl = $row['last_dl'];

// To seconds from 1970
$last_dl = strtotime($last_dl); //120
$seventy_two_hours_in_seconds = 60 * 60 * 72;

if (time() > ($last_dl + $seventy_two_hours_in_seconds)) {
    echo "72 Passed";
} else {
    $wait = date('U', $last_dl + $seventy_two_hours_in_seconds) - date('U'); // seconds for wait
    $hours = floor($wait /3600);
    $min = floor(($wait / 60) % 60);
    $sec = $wait % 60;
    echo "You need to wait: ". $hours. ':'. $min.':'.$sec ."\n";
}

http://sandbox.onlinephpfunctions.com/code/08477cd78c82dfe2b4a5c5f4aee6414866999a8c

检查数据库中字段的剩余时间

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