Question

我有一个nvarchar列，当我选择使用以下查询时，它会给出以下输出 -

SELECT DISTINCT [VERSION]   
FROM IMPORT.BUDGETIMPORT 
WHERE VERSION LIKE 'Test'+'18'+'%' 
ORDER BY [VERSION] ASC

输出：

Test18
Test18.1
Test18.10
Test18.2
Test18.3
Test18.4
Test18.5
Test18.6

我想在选择 -

时按编号订购

Test18
Test18.1
Test18.2
Test18.3
Test18.4
Test18.5
Test18.6
Test18.10

我怎么能只根据数字排序。

Answer 1

试试这个。

首先按字符串的长度排序，然后按字符串本身排序。

<强>查询

SELECT [VERSION]
FROM IMPORT.BUDGETIMPORT 
WHERE [VERSION] LIKE 'Test18'+'%' 
GROUP BY [VERSION]  
ORDER BY LEN([VERSION]), [VERSION];

<强> demo

Answer 2

对于数值数据类型，18.1与18.10相同对于字符串数据类型，18.10将在18.2之前出现

尝试使用以下方法获得预期结果

declare @t table
(
    [version] nvarchar(50)
)

insert into @t
values('Test18'),
('Test18.1'),
('Test18.10'),
('Test18.2'),
('Test18.3'),
('Test18.4'),
('Test18.5'),
('Test18.2'),
('Test18.3'),
('Test18.4'),
('Test18.5'),
('Test18.6')

;with cte
as
(
    select 
        rn = ROW_NUMBER() OVER(PARTITION BY [VERSION] ORDER BY [VERSION]),
        ln = LEN([VERSION]),
        [version] 
        from @t 
)
select
    *
    from cte
        WHERE rn = 1
        order by ln

Answer 3

执行此操作的另一个选项是将版本转换为float;

SELECT DISTINCT [VERSION], cast(SUBSTRING([VERSION], 5, 10) as float) as VersionAsFloat
FROM IMPORT.BUDGETIMPORT 
WHERE VERSION LIKE 'Test'+'18'+'%' 
ORDER BY VersionAsFloat ASC

如何在4个字符后对nvarchar列进行排序？

3 个答案: