Question

我有两个对象：

OBJ1

{
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "qty_min": 0,
  "qty_med": 0,
  "qty_max": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
}

OBJ2

{
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
}

如何删除obj2中不存在的复制和获取元素，以便我的新obj将是：

newObj

{
  "qty_min": 0,
  "qty_med": 0,
  "qty_max": 0,
}

我可以使用lodash pick，但我不想手动输入我要过滤的密钥名称。

const newObj = pick(obj1, [
  'qty_min',
  'qty_med',
  'qty_max',
]);

提前致谢。

Answer 1

使用lodash，您可obj1 obj2 const obj1 = {"uuid":"","open_bal_qty":0,"open_bal_value":0,"qty_min":0,"qty_med":0,"qty_max":0,"kedai_uuid":"198ceaef-4ced-4207-9ba0-62afbb42bb85"}; const obj2 = {"uuid":"","open_bal_qty":0,"open_bal_value":0,"kedai_uuid":"198ceaef-4ced-4207-9ba0-62afbb42bb85"}; const newObj = _.omit(obj1, _.keys(obj2)); console.log(newObj); <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script> {/ 3}}：

{{1}}

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Answer 2

您可以将_.pick与_.difference结合使用，找出两个对象之间的区别＆＃39;钥匙和挑选这些钥匙：

＆＃13;

const obj1 = {
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "qty_min": 0,
  "qty_med": 0,
  "qty_max": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
};

const obj2 = {
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
};

const obj1Keys = _.keys(obj1); //or Object.keys
const obj2Keys = _.keys(obj2);
console.log(_.pick(obj1Keys > obj2Keys ? obj1 : obj2, _.difference(obj1Keys, obj2Keys)))

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>

＆＃13;

Answer 3

使用for..in迭代对象，Object.hasOwnProperty检查第二个对象是否具有相同的密钥

var obj1 = {
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "qty_min": 0,
  "qty_med": 0,
  "qty_max": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
}
var obj2 = {
  "uuid": "",
  "open_bal_qty": 0,
  "open_bal_value": 0,
  "kedai_uuid": "198ceaef-4ced-4207-9ba0-62afbb42bb85"
}
var newObj = {};
for (var keys in obj1) {
  if (!obj2.hasOwnProperty(keys)) {
    newObj[keys] = obj1[keys]
  }
}

console.log(newObj)

删除对象中的重复元素并保留唯一元素

3 个答案: