Question

我正在尝试避免光标从当前格式获取以下所需的输出。目前我必须使用光标，因为数据集非常庞大，我需要大约2个小时来运行它。有没有办法避免光标

这是我目前的代码

Declare @CustomerId CHAR(8)
Declare @StartDate DateTime
Declare @PlStartDate DateTime
Declare @ProviderNo CHAR(8)
Declare @Code CHAR(3)       

Declare @PreviousCustomerId CHAR(8)
Declare @PreviousStartDate DateTime
Declare @PreviousRealStartDate DateTime
Declare @PreviousProviderNo CHAR(8)
Declare @PreviousCode CHAR(3)           
Declare @RowNumber smallint 
Declare @providers CURSOR

SET @providers = CURSOR  FAST_FORWARD  FOR
Select CustomerId, StartDate, PlStartDate, ProviderNo, Code, ProviderSSN, RowNumber  
From dbo.[provider] ORDER by CustomerId, StartDate

OPEN @providers 
FETCH NEXT From @providers  INTO @CustomerId, @StartDate, @PlStartDate,@ProviderNo, @Code, @ProviderSSN, @RowNumber 

WHILE @@FETCH_STATUS = 0
BEGIN  

    If @RowNumber <>1 AND @CustomerId = @PreviousCustomerId AND @Code = @PreviousCode AND (@ProviderNo = @PreviousProviderNo)       
    BEGIN   
        Update dbo.provider
        SET StartDate = @PreviousRealStartDate
        Where CustomerId = @CustomerId AND  StartDate = @StartDate;     
    END
    ELSE
    BEGIN
        Set @StartDate = @StartDate;

        Update dbo.provider
        Set StartDate = @StartDate
        Where CustomerId = @CustomerId AND  StartDate = @StartDate
    END

    Set @PreviousCustomerId = @CustomerId
    Set @PreviousCode = @Code       
    Set @PreviousProviderNo =  @ProviderNo 
    if @StartDate IS NOT NULL
        Set @PreviousRealStartDate = @StartDate
    Set @PreviousStartDate = @StartDate

    FETCH NEXT From @providers INTO @CustomerId, @StartDate, @PlStartDate,@ProviderNo, @Code, @RowNumber        
END 

CLOSE @providers
DEALLOCATE @providers

当前格式

               
Cust ID Start Date      End Date    Code    Provider
7063903 2/11/2009   2/17/2009   DEF 485960
7063903 2/17/2009   2/24/2009   DEF 485960
7063903 2/24/2009   4/6/2009    LHF 479407
7063903 4/6/2009    9/11/2009   DEF 487398
7063903 8/31/2010   9/1/2010    DEF 487398
7063903 8/28/2011   11/25/2011  ABC 531428
7063903 3/1/2012    6/25/2012   DEF 487398
7063903 6/25/2012   3/22/2013   DEF 487398
7063903 3/22/2013   4/23/2014   DEF 487398
7063903 4/23/2014   5/1/2014    DEF 487398
7063903 5/1/2014    7/1/2015    DEF 487398
7063903 7/1/2015    8/28/2015   DEF 531428
7063903 8/28/2015   11/25/2015  ABC 531428
7063903 11/25/2015  9/21/2016   ABC 531428

Desired Output              

CustID  Start Date  End Date    Code    Provider
7063903 2/11/2009   2/24/2009   DEF 485960
7063903 2/24/2009   4/6/2009    LHF 479407
7063903 4/6/2009    9/1/2010    DEF 487398
7063903 8/28/2011   11/25/2011  ABC 531428
7063903 4/6/2009    7/1/2015    DEF 487398
7063903 7/1/2015    8/28/2015   DEF 531428
7063903 8/28/2015   9/21/2016   ABC 531428

Answer 1

  SELECT customer
       , code
       , provider
       , MIN (start_date) start_date
       , MAX (end_date) end_date
    FROM dbo.provider
GROUP BY customer, code, provider;

当提供程序重复如下时，此解决方案失败。看看红色箭头：

汤姆，

我必须道歉，我误解了原来的问题。您希望将答案分组在客户/代码/提供商相同的位置，并且开始日期=上一个结束日期。

下面的SQL通过在客户/代码/提供商不匹配时设置值1，或者开始日期不等于上一个结束日期来执行此操作。然后，我将之前记录中的所有1的总和相加，以创建我可以分组的值。然后我按原始答案执行最小/最大，这次包括小组。

我得到了你要求的相同答案，但有一个例外。您的第一个箭头应该是两行，而不是一行。请试一试。

谢谢，

-Brian

WITH
    aset
    AS
        (SELECT customer
              , code
              , provider
              , start_date
              , end_date
              , CASE
                    WHEN LAG (customer)
                             OVER (
                                 PARTITION BY customer, code, provider ORDER BY end_date
                             ) = customer
                     AND LAG (provider)
                             OVER (
                                 PARTITION BY customer, code, provider ORDER BY end_date
                             ) = provider
                     AND LAG (code)
                             OVER (
                                 PARTITION BY customer, code, provider ORDER BY end_date
                             ) = code
                     AND LAG (end_date)
                             OVER (
                                 PARTITION BY customer, code, provider ORDER BY end_date
                             ) = start_date
                    THEN
                        0
                    ELSE
                        1
                END
                    flag
           FROM deleteme_tbl),
    bset
    AS
        (SELECT customer
              , code
              , provider
              , flag
              , start_date
              , end_date
              , SUM (flag)
                    OVER (
                        ORDER BY
                            customer
                          , code
                          , provider
                          , start_date
                        RANGE UNBOUNDED PRECEDING
                    )
                    grp
           FROM aset)
  SELECT customer
       , code
       , provider
       , MIN (start_date) start_date
       , MAX (end_date) end_date
    FROM bset
GROUP BY customer
       , code
       , provider
       , grp
ORDER BY customer
       , code
       , provider
       , start_date;

Answer 2

是的，改为使用窗口函数，考虑使用LAG（）

Select
       CustomerId
      , StartDate
      , PlStartDate
      , ProviderNo
      , Code
      , ProviderSSN
      , RowNumber 
      , LAG(StartDate) OVER(PARTITION BY CustomerId, Code, ProviderNo 
                            ORDER by StartDate) as lag_date
From dbo.[provider] 
WHERE StartDate IS NULL
ORDER by CustomerId, StartDate

如果这是正确的，您可以将其用于公用表表达式，然后使用它进行更新。不过先测试一下小东西。 e.g。

with cte as ( query shown above )
update cte
set StartDate = lag_date

避免SQL Server中的游标

2 个答案: