Question

我有代码示例：

$ou = 'OU=Security Groups,DC=mydomain,DC=local'

$basepath =  '\\mydomain\dfsroot'

$filter = '*501*'

Get-ADGroup -SearchBase $ou -Filter { Name -like $filter } | % {
    $principle = $_.samAccountName
    Get-ChildItem -LiteralPath $basepath -Recurse | % {
        $path = $_.FullName
        ($path | Get-Acl).Access.IdentityReference | % { if ( $_.Value -match $principle ) { Write-Host "$principle has rights to $path" }}
    }
}

我的问题是如何在字符串很大且未在$str = '123456789101112131415'; if(strlen($str) <9 ) { echo "the string is 10"; } elseif(strlen($str) > 9) { echo 'the string is 11'; } elseif(strlen($str) > 21) { echo 'the string is 30'; } elseif(strlen($str) > 31) { echo 'the string is 40'; }条件中指定

时进行整理

Answer 1

计算它！

致电strlen()
除以10
调用floor()删除小数
乘以10
检查是否小于10

以下是一系列测试：

代码：（Demo）

$strings=[9=>'123456789',10=>'1234567890',11=>'12345678901',19=>'1234567890123456789',20=>'12345678901234567890',21=>'123456789012345678901'];
foreach($strings as $k=>$str){
    if(($group=floor(strlen($str)/10)*10)<10){  // use arithmetic to find the group, declare and check group in one step
        echo "$k => $str is not upto 10";
    }else{
        echo "$k => $str is in group $group";
    }
    echo "\n";
}

输出：

9 => 123456789 is not upto 10
10 => 1234567890 is in group 10
11 => 12345678901 is in group 10
19 => 1234567890123456789 is in group 10
20 => 12345678901234567890 is in group 20
21 => 123456789012345678901 is in group 20

OP更新后：

代码：（Demo）

$strings=[9=>'123456789',10=>'1234567890',11=>'12345678901',19=>'1234567890123456789',20=>'12345678901234567890',21=>'123456789012345678901'];
foreach($strings as $k=>$str){
    echo "$k => $str is in group ",(floor(strlen($str)/10)+1)*10,"\n";
}

输出：

9 => 123456789 is in group 10
10 => 1234567890 is in group 20
11 => 12345678901 is in group 20
19 => 1234567890123456789 is in group 20
20 => 12345678901234567890 is in group 30
21 => 123456789012345678901 is in group 30

这是另一种方法，它完全提供了OP要求的内容，但我敢打赌它也“不对”。

http://sandbox.onlinephpfunctions.com/code/77effe7f68c389bafb1d104a49b7055873e7b038

如果没有条件，我如何计算字符串中的字符？

1 个答案: