Question

从字符串示例

计算每个框中的每个字符

   $str = 'man[big man]boy[big]guy[badforreal] and others';

预期结果：

你有6个字符（男）

你有3个字符（男孩）
     你有10个字符（男）

我能在PHP中真正实现这一目标吗？

Answer 1

扩展preg_match_all解决方案：

$str = 'man[big man]boy[big]guy[badforreal] and others';
preg_match_all('/([^\s\[\]]+)\[([^\[\]]+)\]/', $str, $matches);

if (isset($matches[1])) {
    foreach ($matches[1] as $k => $m) {
        printf("%s characters for (%s)\n", strlen(str_replace(" ", "", $matches[2][$k])), $m);
    }
}

输出：

6 characters for (man)
3 characters for (boy)
10 characters for (guy)

Answer 2

你可以试试这个

$array = explode("]", $str);
foreach ($array as $string){
    if( strpos($string, '[') !== false ){
        $strLabel = strstr($string, '[', true);
        $newStr .= "you have " . strlen(str_replace(["["," "], "", strstr($string, '['))) ." characters for (" . $strLabel .")<br/>";
    }
}
echo $newStr;

预期产出

you have 6 characters for (man)
you have 3 characters for (boy)
you have 10 characters for (guy)

如何计算括号内的每个字符

2 个答案: