Question

在我的脚本中，我想在我的字典中包含一个键并创建一个条件，如果我已经有相同键的重复值，则不会包含它。

以FIle为例： https://raw.githubusercontent.com/felipelira/files_to_test/master/GCF_000302915.1_Pav631_1.0_genomic.gbff

for seq_record in SeqIO.parse(input_file, "genbank"):
    description = seq_record.description
    for seq_feature in seq_record.features:
        if seq_feature.type=="source":
            try:
                source = seq_feature.qualifiers['organism'][0]
            except (KeyError, IndexError):
                source = 'n/a'

            try: 
                strain = seq_feature.qualifiers['strain'][0]
            except (KeyError, IndexError):
                strain = 'n/a'
                    if source not in dict1.keys():
                        dict1[source] = [value]
                        #print description +'\t'+ source +'\t'+ '\t'.join(value)
                    else:
                        if source in dict1.keys() and value != dict1[source]:   
                            dict1[source].append(value)
                        #print description +'\t'+source +'\t'+ '\t'.join(value)

        for k, v in dict1.iteritems():
            print k, v

Answer 1

只需将!=替换为not in，即：

        try: 
            strain = seq_feature.qualifiers['strain'][0]
        except (KeyError, IndexError):
            strain = 'n/a'
                if source not in dict1.keys():
                    dict1[source] = [value]
                    #print description +'\t'+ source +'\t'+ '\t'.join(value)
                else:
                    if source in dict1.keys() and value not in dict1[source]:   
                        dict1[source].append(value)
                    #print description +'\t'+source +'\t'+ '\t'.join(value)

Answer 2

为了不向已包含此值的列表添加值，您可以使用in运算符检查成员身份。像这样：

if not value in dict1[source]:   
    dict1[source].append(value)

如果您不需要将字典值作为列表，请考虑使用set，该http://server01:9090/api/v1/query_range?query=node_exporter_metrics&start=1513255115&end=1513258715&step=60已针对保持其成员的唯一性进行了优化。

没有重复值的字典

2 个答案: