Question

我已经阅读了一些关于约束的内容，并尝试在我的存储库模式中实现它。

我想要类似下面的内容，但无法完全编译。

 public interface IRepository<T>
 {
    void GetAllData<T>();
 }

 //This needs to inherit from IRepository
 //T has to be a model class
 //V has to be a class that implements IEmployeeRepo
 public interface IEmployeeRepo<T, V> where V : EmployeeRepo where T : class : IRepository<T>
 {
    void DoSomethingEmployeeRelated();
 }

 //Dont think this inheritance is correct
 public class EmployeeRepo<Employee, this> : IEmployeeRepo
 {


 }

 //My example model class
 public class Employee
 {
     public string Name {get;set;}
 }

Answer 1

不确定为什么在存储库中有两个类型参数 - 重点是什么？

* 以下是使用泛型的.NET存储库的经典示例：*

* 首先，存储库接口：*

public interface IRepository<T> where T : class
{
   T FindSingle(Expression<Func<T,bool>> predicate);
   IQueryable<T> FindAll(); // optional - matter of preference
   void Add(T entity);
   void Remove(T entity);
}

* 其次，通用存储库实现（以EF为例）：*

public abstract class GenericRepository<T> : IRepository<T>
{
   private IObjectSet<T> _ObjectSet; // get this in via DI (for example)

   public T FindSingle(Expression<T,bool>> predicate)
   {
      return _ObjectSet.SingleOrDefault(predicate);
   }

   // you can figure out how to do the other implementation methods
}

* 然后，特定存储库（每个聚合根应该有一个，并且还有每个特定存储库的接口，详细说明特定方法）：*

public EmployeeRepository : GenericRepository<Employee>, IRepository<Employee>
{
   // all regular methods (Find, Add, Remove) inherited - make use of them
   public Employee FindEmployeeByName(string name)
   {
      return FindAll().SingleOrDefault(x => x.Name == name);
      // or you could do: return FindSingle(x => x.Name == name);    
   }
}

<强>用法：

IRepository<Employee> repository = new EmployeeRepository<Employee>();

不要因为泛型而过于疯狂 - 你唯一需要的是限制Repository被封装在Repository背后的实体使用。

我只是使用where T : class。

其他人使用where T : IDomainAggregate或类似物来限制实际允许的实体类型。

Answer 2

在这种情况下，我通常有一个实现IRepository＆lt;＆gt;的基础repo类，并且输入到基础Model类。

public interface IRepository<T> where T : IModel
 {
    void GetAll<T>();
    void GetById<T>(int id);
 }    

 public interface IEmployeeRepo<T> : IRepository<T> where T : IModel
 {
    void DoSomethingEmployeeRelated();
 }

 public class BaseRepo : IRepository<T> where T : IModel
 {

    public void GetAll<T>()
    {

    }

    public void GetById<T>(int id)
    {

    }
 }


 public class EmployeeRepo : BaseRepo<Employee>,  IEmployeeRepo<Employee>
 {
    public void DoSomethingEmployeeRelated()
    {

    }

 }

 //My example model class
 public class Employee : IModel
 {
     public int Id {get;set;}
     public string Name {get;set;}
 }

Answer 3

试试这个;

public interface IRepository<T>
 {
    void GetAllData<T>();
 }

 //This needs to inherit from IRepository
 //T has to be a model class
 //V has to be a class that implements IEmployeeRepo
 public interface IEmployeeRepo<T, V> : IRepository<T> where V : EmployeeRepo where T : class
 {
    void DoSomethingEmployeeRelated();
 }

 //Dont think this inheritance is correct
 public class EmployeeRepo : IEmployeeRepo<Employee, EmployeeRepo>
 {
    public void DoSomethingEmployeeRelated()
    {

    }

    public void GetAllData<Employee>()
    {

    }
 }

 //My example model class
 public class Employee
 {
     public string Name {get;set;}
 }

存储库模式的通用接口继承和类实现

3 个答案: