Question

我有一个如下列表：

['0.0000    0.0012    0.0024    0.0037    0.0049', '0.0061    0.0073    0.0085    0.0097    0.0110', '0.0122    0.0134    0.0146    0.0158    0.0170', '1.0000']

我想从中删除撇号，逗号和空格，并将项目附加到新列表中。输出应如下所示：

[0.0000,0.0012,0.0024,0.0037,0.0049,0.0061,0.0073,0.0085,0.0097,0.0110,0.0122,0.0134,0.0146,0.0158,0.0170,1.0000]

这可能是一项微不足道的任务。有什么建议？

Answer 1

简单的单行：split（没有参数，因此它具有将任何数量的空格字符作为分隔符的优点），在列表理解中被2个非嵌套循环展平，同时转换为float：

a = ['0.0000    0.0012    0.0024    0.0037    0.0049', '0.0061    0.0073    0.0085    0.0097    0.0110', '0.0122    0.0134    0.0146    0.0158    0.0170', '1.0000']

result = [float(x) for e in a for x in e.split()]

print(result)

结果：

[0.0, 0.0012, 0.0024, 0.0037, 0.0049, 0.0061, 0.0073, 0.0085, 0.0097, 0.011, 0.0122, 0.0134, 0.0146, 0.0158, 0.017, 1.0]

Answer 2

你可以试试这个：

import re
import itertools
s = ['0.0000    0.0012    0.0024    0.0037    0.0049', '0.0061    0.0073    0.0085    0.0097    0.0110', '0.0122    0.0134    0.0146    0.0158    0.0170', '1.0000']
new_s = map(float, itertools.chain(*[re.split('\s+', i) for i in s]))

输出：

[0.0, 0.0012, 0.0024, 0.0037, 0.0049, 0.0061, 0.0073, 0.0085, 0.0097, 0.011, 0.0122, 0.0134, 0.0146, 0.0158, 0.017, 1.0]

Answer 3

请注意，该列表不包含撇号和逗号。这些是输出的一部分，以显示列表包含字符串。逗号分隔列表中的每个字符串，有一个撇号用于显示字符串的开头，另一个用于显示字符串的结尾。

要管理空白，您可能需要使用split()。如果在每个字符串上调用此函数，您将获得数字的各个字符串表示形式。如果您想要数字而不是字符串，则需要将它们转换为float s。这将允许您对数据进行数值运算。

Answer 4

x = ['0.0000    0.0012    0.0024    0.0037    0.0049', '0.0061    0.0073    0.0085    0.0097    0.0110', '0.0122    0.0134    0.0146    0.0158    0.0170', '1.0000']
list_x = []

for i in x:
    list_x.append(i.split('    ')) # Erase 4 whitespaces, add values to a list.

list_final = [a for b in list_x for a in b] # Combine lists.

将空白分隔数字列表转换为浮点数列表

4 个答案: