Question

有人知道为什么缩放功能仅在我越过节点而不是在svg上时触发？当鼠标在svg上方时，我想要缩放功能，而不仅仅是在节点上。如果有人可以帮助我，那将是非常好的。也许有人知道如何将pan添加到图表中？平移图表没有最高优先级。缩放图表更为重要。 JS Fiddle

$(document).ready(function() {
// DATA is a JSON objekt --> see in fiddle
  let data = DATA                   
  var margin = {
      top: 20,
      right: 120,
      bottom: 20,
      left: 120
    },
    width = 960 - margin.right - margin.left,
    height = 500 - margin.top - margin.bottom;

  var i = 0,
    duration = 750,
    root;

  var tree = d3.layout.tree()
    .size([height, width]);

  var diagonal = d3.svg.diagonal()
    .projection(function(d) {
      return [d.y, d.x];
    });

  var zoomListener = d3.behavior.zoom().scaleExtent([0.1, 3]).on("zoom", zoom);

  function zoom() {
    console.log('====================================');
    console.log("zoom is only on node?");
    console.log('====================================');
  }

  var svg = d3.select("#tree-svg")
    .attr("width", width + margin.right + margin.left)
    .attr("height", height + margin.top + margin.bottom)
    .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")")
    .call(zoomListener)
  draw(data)
  function draw(data) {
    //if (error) throw error;
    let flare = data
    root = flare;
    root.x0 = height / 2;
    root.y0 = 0;

    function collapse(d) {
      if (d.children) {
        d._children = d.children;
        d._children.forEach(collapse);
        d.children = null;
      }
    }

    root.children.forEach(collapse);
    update(root);
  }

  d3.select(self.frameElement).style("height", "800px");
  function update(source) {
    // Compute the new tree layout.
    var nodes = tree.nodes(root).reverse(),
      links = tree.links(nodes);

    // Normalize for fixed-depth.
    nodes.forEach(function(d) {
      d.y = d.depth * 180;
    });

    // Update the nodes…
    var node = svg.selectAll("g.node")
      .data(nodes, function(d) {
        return d.id || (d.id = ++i);
      });

    // Enter any new nodes at the parent's previous position.
    var nodeEnter = node.enter().append("g")
      .attr("class", "node")
      .attr("transform", function(d) {
        return "translate(" + source.y0 + "," + source.x0 + ")";
      })
      .on("click", click);


    nodeEnter.append("circle")
      .attr("r", 1e-6)
      .style("fill", function(d) {
        return d._children ? "lightsteelblue" : "#fff";
      });
    nodeEnter.append("text")
      .attr("x", function(d) {
        return d.children || d._children ? -10 : 10;
      })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) {
        return d.children || d._children ? "end" : "start";
      })
      .text(function(d) {
        return d.name;
      })
      .style("fill", "black");

    // Transition nodes to their new position.
    var nodeUpdate = node.transition()
      .duration(duration)
      .attr("transform", function(d) {
        return "translate(" + d.y + "," + d.x + ")";
      });

    nodeUpdate.select("circle")
      .attr("r", 4.5)
      .style("fill", function(d) {
        return d._children ? "lightsteelblue" : "#fff";
      });

    nodeUpdate.select("text")
      .style("fill-opacity", 1);

    // Transition exiting nodes to the parent's new position.
    var nodeExit = node.exit().transition()
      .duration(duration)
      .attr("transform", function(d) {
        return "translate(" + source.y + "," + source.x + ")";
      })
      .remove();

    nodeExit.select("circle")
      .attr("r", 1e-6);

    nodeExit.select("text")
      .style("fill-opacity", 1e-6);

    // Update the links…
    var link = svg.selectAll("path.link")
      .data(links, function(d) {
        return d.target.id;
      });

    // Enter any new links at the parent's previous position.
    link.enter().insert("path", "g")
      .attr("class", "link")
      .attr("d", function(d) {
        var o = {
          x: source.x0,
          y: source.y0
        };
        return diagonal({
          source: o,
          target: o
        });
      });

    // Transition links to their new position.
    link.transition()
      .duration(duration)
      .attr("d", diagonal);

    // Transition exiting nodes to the parent's new position.
    link.exit().transition()
      .duration(duration)
      .attr("d", function(d) {
        var o = {
          x: source.x,
          y: source.y
        };
        return diagonal({
          source: o,
          target: o
        });
      })
      .remove();

    // Stash the old positions for transition.
    nodes.forEach(function(d) {
      d.x0 = d.x;
      d.y0 = d.y;
    });
  }

  // Toggle children on click.
  function click(d) {

    if (d.children) {
      d._children = d.children;
      d.children = null;
    } else {
      d.children = d._children;
      d._children = null;
    }
    update(d);
  }
})

Answer 1

您需要附加一个包含所有节点的组，并且缩放侦听器可以对其进行操作。

dependencies {
     compile "com.android.support:support-v4:26.1+"
}

请参阅此示例http://bl.ocks.org/robschmuecker/7880033。 Pan也显示在那里。

d3树图缩放仅在节点上

1 个答案: