我正在尝试在我的控制器中使用findAll()
方法。我写了一个存储库,模型和控制器作为例子。但是,当我运行的网址显示“此应用程序没有显示/错误的显式映射时,所以您将此视为后备”
我的控制器是:
@RestController
public class WebController {
@Autowired
UsersRepository userRepo;
@GetMapping("/loadAuthUsers")
public List<Users> checkLogin() {
return (List<Users>) userRepo.findAll();
}
}
我的模特是,
@Entity
@Table(name = "users")
public class User implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@Column(name = "username")
public String username;
@Column(name = "password")
public String password;
@Column(name = "uia_token")
public String uia_token;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUia_token() {
return uia_token;
}
public void setUia_token(String uia_token) {
this.uia_token = uia_token;
}
public User() {
}
public User(Integer userId, String username, String password , String
uia_token) {
this.username = username;
this.password = password;
this.uia_token = uia_token;
}
}
我的存储库是,
@Repository
public interface UserRepository extends CrudRepository<User, Integer> {
}
我的application.properties包含,
spring.datasource.url=jdbc:postgresql://localhost/espace
spring.datasource.username=postgres
spring.datasource.password=postgresql
spring.jpa.generate-ddl=true
server.port=8081
我的主要课程是,
@SpringBootApplication
@Configuration
@ComponentScan("com.milletech.services.repository")
public class EspaceCheckAuthenticationApplication {
public static void main(String[] args) {
SpringApplication.run(EspaceCheckAuthenticationApplication.class, args);
}
}
任何人都可以帮忙解决这个映射问题吗?
答案 0 :(得分:1)
根据日志,它会自动连接错误。
您需要使用 @Repository 注释 UserRepository 类,以便进行自动装配。
工作代码为:
@SpringBootApplication
@EnableJpaRepositories(considerNestedRepositories = true)
public class MyApplication {
public static void main(String[] args) throws Exception {
SpringApplication.run(MyApplication.class, args);
}
}
在Spring应用程序类中添加注释 @EnableJpaRepositories :
Kernel.php