使用ssh命令时，subprocess.Popen shell = True to shell = False

Question

我有命令：

proc = subprocess.Popen(["sshpass -p root ssh root@(IP_ADRESS) 'cd
/home/pi/reed && python reed.py'"],  shell=True,
stdin=subprocess.PIPE, stdout=subprocess.PIPE, )

shell=True很危险，所以我想避开它并使用shell=False。

任何提示？

Answer 1

您应该拆分命令。像这样：

proc = subprocess.Popen("sshpass -p root ssh root@(IP_ADRESS) 'cd /home/pi/reed && python reed.py'".split(), stdin=subprocess.PIPE, stdout=subprocess.PIPE, )

Answer 2

也许这个？

proc = subprocess.Popen(["sshpass", "-p", "root", "ssh", "root@(IP_ADRESS)", "cd /home/pi/reed && python reed.py"], stdin=subprocess.PIPE, stdout=subprocess.PIPE, )