我使用symfony 3.4.1和doctrine/doctrine-fixtures-bundle": "2.4.1
我试图运行灯具,但是当我尝试注入UserPasswordEncoderInterface
来编码我的密码时,我收到了此消息。
https://symfony.com/doc/master/bundles/DoctrineFixturesBundle/index.html#accessing-services-from-the-fixtures
致命错误:未捕获 Symfony \ Component \ Debug \ Exception \ FatalThrowableError:输入错误:太多 很少有功能论据 AppBundle \ DataFixtures \ DataFixtures :: __ construct(),0传入 /srv/api-platform/vendor/doctrine/data-fixtures/lib/Doctrine/Common/DataFixtures/Loader.php 在第210行和预期的1 /srv/api-platform/src/AppBundle/DataFixtures/ORM/DataFixtures.php:20 堆栈跟踪:
0 /srv/api-platform/vendor/doctrine/data-fixtures/lib/Doctrine/Common/DataFixtures/Loader.php(210):
的appbundle \ DataFixtures \ DataFixtures-> __构建体()
1 /srv/api-platform/vendor/doctrine/data-fixtures/lib/Doctrine/Common/DataFixtures/Loader.php(390):
学说\共同\ DataFixtures \装载机> createFixture('的appbundle \ DATAF ...&#39)
2 /srv/api-platform/vendor/doctrine/data-fixtures/lib/Doctrine/Common/DataFixtures/Loader.php(82):
学说\共同\ DataFixtures \装载机> loadFromIterator(对象(RecursiveIteratorIterator))
3 /srv/api-platform/vendor/doctrine/doctrine-fixtures-bundle/Command/LoadDataFixturesDoctrineCommand.php(102):
Doctrine \ Commo in /srv/api-platform/src/AppBundle/DataFixtures/ORM/DataFixtures.php on 第20行
我的赛程:
<?php
namespace AppBundle\DataFixtures;
use AppBundle\Entity\TechnicalCenter;
use AppBundle\Entity\User;
use Doctrine\Bundle\FixturesBundle\Fixture;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
class DataFixtures extends Fixture
{
/** @var UserPasswordEncoderInterface $encoder */
private $encoder;
/**
* DataFixtures constructor.
* @param UserPasswordEncoderInterface $encoder
*/
public function __construct(UserPasswordEncoderInterface $encoder)
{
$this->encoder = $encoder;
}
/**
* Load data fixtures with the passed EntityManager
*
* @param ObjectManager $manager
*/
public function load(ObjectManager $manager)
{
$technicalCenter = new TechnicalCenter();
$technicalCenter->setName('Austerlitz');
$manager->persist($technicalCenter);
$admin = new User();
$admin->setUsername('admin');
$admin->setPassword($this->encoder->encodePassword($admin, 'admin'));
$admin->setRoles(array('ROLE_ADMIN'));
$admin->setTechnicalCenter($technicalCenter);
$manager->persist($admin);
$manager->flush();
}
}
我的security.yml
security:
encoders:
AppBundle\Entity\User: bcrypt
答案 0 :(得分:4)
在fixture中,我通过实现它并使用&#34; setContainer&#34;直接注入ContainerInterface。函数,例如:
<?php
namespace CoreBundle\DataFixtures\ORM;
use CoreBundle\Entity\Admin;
use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\DataFixtures\OrderedFixtureInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\DependencyInjection\ContainerAwareInterface;
use Symfony\Component\DependencyInjection\ContainerInterface;
class LoadAdminData extends AbstractFixture implements OrderedFixtureInterface, ContainerAwareInterface {
/**
* @var ContainerInterface
*/
private $container;
public function setContainer(ContainerInterface $container = null)
{
$this->container = $container;
}
/**
* {@inheritDoc}
*/
public function load(ObjectManager $manager)
{
$admin = new Admin();
$admin->setUsername('Test');
$plainPass = 'admin';
$encoder = $this->container->get('security.password_encoder');
$encodedPass = $encoder->encodePassword($admin, $plainPass);
$admin->setPassword($encodedPass);
$admin->setEmail('test@test.com');
$manager->persist($admin);
$manager->flush();
}
public function getOrder()
{
// the order in which fixtures will be loaded
// the lower the number, the sooner that this fixture is loaded
return 1;
}
}