Question

在iPhone App中，在设备上运行App时如何检测正在运行App的设备的屏幕分辨率？

Answer 1

CGRect screenBounds = [[UIScreen mainScreen] bounds];

这将为您提供整个屏幕的分辨率，因此对于iPhone来说，最典型的是320x480。尽管iPhone4的屏幕尺寸要大得多，但iOS仍然可以提供320x480而不是640x960。这主要是因为较旧的应用程序崩溃。

CGFloat screenScale = [[UIScreen mainScreen] scale];

这将为您提供屏幕比例。对于没有Retina显示器的所有设备，这将返回1.0f，而Retina显示设备将提供2.0f，而iPhone 6 Plus（Retina HD）将提供3.0f。

现在，如果你想获得像素宽度＆amp; iOS设备屏幕的高度你只需要做一件简单的事情。

CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);

通过乘以屏幕的比例，您可以得到实际的像素分辨率。

有关iOS中点和像素之间差异的详细信息，请阅读here。

编辑：（Swift版本）

let screenBounds = UIScreen.main.bounds
let screenScale = UIScreen.main.scale
let screenSize = CGSize(width: screenBounds.size.width * screenScale, height: screenBounds.size.height * screenScale)

Answer 2

UIScreen类可让您以点和像素找到屏幕分辨率。

屏幕分辨率以点数或像素数衡量。它绝不应与屏幕尺寸混淆。较小的屏幕尺寸可以具有更高的分辨率。

UIScreen的'bounds.width'返回点

中的矩形大小

UIScreen的'nativeBounds.width'以像素为单位返回矩形大小。此值被检测为PPI（每英寸点数）。显示锐度＆amp;设备上图像的清晰度。

您可以使用UIScreen类来检测所有这些值。

<强> Swift3

// Normal Screen Bounds - Detect Screen size in Points.
let width = UIScreen.main.bounds.width
let height = UIScreen.main.bounds.height
print("\n width:\(width) \n height:\(height)")

// Native Bounds - Detect Screen size in Pixels.
let nWidth = UIScreen.main.nativeBounds.width
let nHeight = UIScreen.main.nativeBounds.height
print("\n Native Width:\(nWidth) \n Native Height:\(nHeight)")

<强>控制台

width:736.0 
height:414.0

Native Width:1080.0 
Native Height:1920.0

Swift 2.x

//Normal Bounds - Detect Screen size in Points.
    let width  = UIScreen.mainScreen.bounds.width
    let height = UIScreen.mainScreen.bounds.height

// Native Bounds - Detect Screen size in Pixels.
    let nWidth  = UIScreen.mainScreen.nativeBounds.width
    let nHeight = UIScreen.mainScreen.nativeBounds.height

<强>的ObjectiveC

// Normal Bounds - Detect Screen size in Points.
CGFloat *width  = [UIScreen mainScreen].bounds.size.width;
CGFloat *height = [UIScreen mainScreen].bounds.size.height;

// Native Bounds - Detect Screen size in Pixels.
CGFloat *width  = [UIScreen mainScreen].nativeBounds.size.width
CGFloat *height = [UIScreen mainScreen].nativeBounds.size.width

Answer 3

在App Delegate中使用它：我正在使用storyboard

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    //----------------HERE WE SETUP FOR IPHONE 4/4s/iPod----------------------

    if(iOSDeviceScreenSize.height == 480){          

        UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"iPhone" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];

        iphone=@"4";

        NSLog(@"iPhone 4: %f", iOSDeviceScreenSize.height);

    }

    //----------------HERE WE SETUP FOR IPHONE 5----------------------

    if(iOSDeviceScreenSize.height == 568){

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
        UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"iPhone5" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];

         NSLog(@"iPhone 5: %f", iOSDeviceScreenSize.height);
        iphone=@"5";
    }

} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
    // NSLog(@"wqweqe");
    storyboard = [UIStoryboard storyboardWithName:@"iPad" bundle:nil];

}

 return YES;
 }

Answer 4

对于iOS 8，我们可以像这样使用[UIScreen mainScreen].nativeBounds：

- (NSInteger)resolutionX
{
    return CGRectGetWidth([UIScreen mainScreen].nativeBounds);
}

- (NSInteger)resolutionY
{
    return CGRectGetHeight([UIScreen mainScreen].nativeBounds);
}

Answer 5

请参阅UIScreen参考：http://developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html

if([[UIScreen mainScreen] respondsToSelector:NSSelectorFromString(@"scale")])
{
    if ([[UIScreen mainScreen] scale] < 1.1)
        NSLog(@"Standard Resolution Device");

    if ([[UIScreen mainScreen] scale] > 1.9)
        NSLog(@"High Resolution Device");
}

Answer 6

使用此代码有助于获取任何类型的设备屏幕分辨率

 [[UIScreen mainScreen] bounds].size.height
 [[UIScreen mainScreen] bounds].size.width

在iPhone App中如何检测设备的屏幕分辨率

6 个答案: