我在PHP中有一个像这样的编号数组
原始阵列:
Array
(
[i] => Array
(
[0] => Array
(
[id] => 1
[qty] => 5
)
[1] => Array
(
[id] => 2
[qty] => 5
)
[2] => Array
(
[id] => 2
[qty] => 5
)
[3] => Array
(
[id] => 1
[qty] => 5
)
[4] => Array
(
[id] => 3
[qty] => 5
)
)
)
我希望它将相同的" id"如果有重复项,请加上数量,如果" id"是键而不是数字键,我应该能够做到。
我的预期结果是:
Array
(
[i] => Array
(
[0] => Array
(
[id] => 1
[qty] => 10
)
[1] => Array
(
[id] => 2
[qty] => 10
)
[2] => Array
(
[id] => 3
[qty] => 5
)
)
)
答案 0 :(得分:1)
工作解决方案
<?php
$your_arr = array(
array('id' => 1,'qty' => 5),
array('id' => 2,'qty' => 5),
array('id' => 2222,'qty' => 5),
array('id' => 1,'qty' => 5),
array('id' => 3,'qty' => 5)
);
$new = array();
foreach ($your_array as $r){
if(!isset($new[$r['id']]))$t=0; //check the current id exist in $new if Not $t = 0;
else $t=$r['qty']; //if yes $t's value become the saved value in $new[$r['id']]
$new[$r['id']]['id'] = $r['id'];
$new[$r['id']]['qty'] = ($t+$r['qty']); // add the new value with $new[$r['id]]'s value.
}
echo "<pre>";print_r($new);
?>
答案 1 :(得分:0)
这可以帮助您将id
作为关键
$filtered_array = array();
foreach($arrayvariable as $eachdata)
{
$filtered_array[$eachdata['id']][] = $eachdata;
}
var_dump($filtered_array);exit;
谢谢,
答案 2 :(得分:0)
使用array_column
可能有更优雅的方法,但我会执行以下操作:
排序:
usort($array, function($a, $b) { return $a['id'] <=> $b['id']; }); /* PHP 7 */
答案 3 :(得分:-1)
除了编写自己的方法处理创建目标数组的原始数组之外,我认为还有其他方法。像这样:
private function processArray($original) {
$target = array();
foreach ($original as $originalEntry) {
foreach ($target as $targetEntry) {
if ($targetEntry['id'] === $originalEntry['id']) {
$targetEntry['qty'] = $targetEntry['qty'] + $originalEntry['qty'];
continue 2;
}
}
$target[] = $originalEntry;
}
return $target;
}
我没有时间测试此方法,但它应该使用相同的id
连接所有条目,将所有qty
字段相加。