我有一张如下表格,
Date Type ClassA ClassB
--------------------------------------------------
02/05/2015 A 1
04/05/2015 B 2 -
04/05/2015 B - 3
05/05/2015 A 4 -
05/05/2015 B 5 -
我正在尝试合并以下行(必需输出)
Date Type ClassA ClassB
--------------------------------------------------
02/05/2015 A 1 -
04/05/2015 B 2 3
05/05/2015 A 4 -
05/05/2015 B 5 -
在上面的例子中,当'日期'和'键入'在2个单独的行中匹配,我应该合并其他列值以成为单行
答案 0 :(得分:2)
ul {
list-style: none;
}
ul#pri.nav {
margin-left: 0px;
z-index: -1;
border-top-right-radius: 15px;
border-top-left-radius: 15px;
text-decoration: none;
width: 97%;
background-color: rgb(180, 221, 180);
}
ul.nav {
height: 10px;
}
ul.nav li {
float: left;
margin-top: 0px;
padding: 10px 13px;
font-family: Arial, sans-serif;
font-size: small;
line-height: 15px;
cursor: pointer;
font-weight: 700;
}
ul.nav#pri li {
margin-top: 0px;
float: left;
margin-right: 5px;
font-family: 'Arial Rounded MT';
color: #fff;
width: 100px;
height: 6px;
text-align: center;
padding: 20px;
display: block;
-moz-border-radius-topleft: 15px;
-webkit-border-top-left-radius: 15px;
-moz-border-radius-topright: 15px;
-webkit-border-top-right-radius: 15px;
border-bottom-style: none;
border-bottom-color: inherit;
border-bottom-width: medium;
background-color: #0fc15e;
position: relative;
bottom: 45px;
}
ul.nav#pri li a {
text-decoration: none;
color: #fff;
}
ul.nav#pri li.active,
ul.nav#pri li:hover ul.nav#sec {
display: block;
font-family: 'Arial Rounded MT';
color: #a67cd5;
}
.nav#pri li:hover ul {
color: #2b95b2;
}
ul.nav#sec {
display: none;
/*float:left;
text-align:center;
border-top-right-radius:15px;
border-top-left-radius:15px;
text-decoration:none;
color:#fff;
font-family:'Arial Rounded MT';
font-size:15px;
color:#fff;
margin-top:-1px;
width:97%;
*/
/*height:25px;
border-top-right-radius:15px;*/
}
/*ul.nav#pri li li.active
{
}*/
ul.nav#sec li a {
text-decoration: none;
color: #fff;
font-size: 14px;
}
ul.nav#sec li:hover {
font-family: 'Arial Rounded MT';
text-decoration: none;
color: #fff;
background-color: #747171;
}
答案 1 :(得分:0)
试试这个:
SELECT date, type, SUM(classA), SUM(classB)
FROM yourtable
GROUP BY date, type