Question

这是我的代码，当我读取必须存储在类中的行，它读取一行并存储下一行的值时，我无法识别代码中的错误。请帮我纠正一下。任务是跳过包含句子的行，并读取数据abd将其存储在类变量中的行。

#include <stdio.h>
#include <iostream>
#include <fstream>
#include <sstream>
#include <stack>
#include <string>

using namespace std;

class data_Read
{
public:
    /* timestamp */
    double time;

    /*state of the signal 1 or 2*/
    unsigned int state;

    /*ID in hexadecimal and converted to decimal*/
    std::string  ID;

    /* Received or transmitted message */
    std::string status;

    /* Message type */
    std::string type;

    /* byte length */
    unsigned int byte_lent;

    /* CAN Message */
    std::string message_1;
    std::string message_2;
    std::string message_3;
    std::string message_4;
    std::string message_5;
    std::string message_6;
    std::string message_7;
    std::string message_8;

    std::string type1;
    std::string type2;
    std::string type3;
    std::string type4;
    std::string type5;
    std::string type6;
    std::string type7;
    std::string type8;
    std::string type9;

};

int main()
{

    std::ifstream ifs("datatrace.txt");
    data_Read data;
    std::string line;

    while (!ifs.eof())
    {

    start:
        std::getline(ifs, line);

        std::cout << line << std::endl;


        if (!isspace(line[0]))
        {
            goto start;
        }
        std::size_t space = line.find(" ", 0);
        if (space == 0)
        {
            int i;
            for (i = 0; i <= 15; i++)
            {
                if (isalpha(line[i]))
                {
                    goto start;
                }   
            }


                    ifs >> data.time >> data.state >> data.ID >> data.status >> data.type >> data.byte_lent >> data.CAN_message_1 >> data.CAN_message_2 >> data.CAN_message_3 >> data.CAN_message_4 >> data.CAN_message_5 >> data.CAN_message_6;
    ifs >> data.CAN_message_7 >> data.CAN_message_8 >> data.type1 >> data.type2 >> data.type3 >> data.type4 >> data.type5 >> data.type6 >> data.type7>> data.type8 >> data.type9;
    cout << data.time << "\t" << data.state << "\t" << data.ID << "\t" << data.status << "\t" << data.type << "\t" << data.byte_lent << "\t" << data.CAN_message_1 << "\t" << data.CAN_message_2 << "\t" << data.CAN_message_3 << "\t";
    cout << data.CAN_message_4 << "\t"<< data.CAN_message_5 << "\t"<< data.CAN_message_6 << "\t" << data.CAN_message_7 << "\t"<< data.CAN_message_8 << "\t"<< data.type1 << "\t"<< data.type2 << "\t"<< data.type3 << "\t"<< data.type4 << "\t"<< data.type5 << "\t" << data.type6 << "\t"<< data.type7 << "\t"<< data.type8 << "\t"<< data.type9 << endl;          
        }
    }
    ifs.close();
    return 0;
}

，文本文件包含

date Fri Sep 1 02:11:40.195 pm 2017
base hex  timestamps absolute
internal events logged
// version 9.0.0
Begin Triggerblock Fri Sep 1 02:11:40.195 pm 2017
   0.000000 Start of measurement
   0.002893 1  201             Rx   d 8 06 0D 00 B0 89 00 0D E7  Length = 227925 BitCount = 118 ID = 513
   0.003133 1  280             Rx   d 8 1B 0C 7C F1 E8 75 39 67  Length = 221910 BitCount = 115 ID = 640
   0.006981 CAN 1 Status:chip status error active
   0.006981 CAN 2 Status:chip status error active
   0.007123 1  244             Rx   d 8 7B 01 00 08 80 80 C0 00  Length = 233925 BitCount = 121 ID = 580
   0.007148 2  B2              Rx   d 8 C0 13 9A 13 D8 13 C0 13  Length = 221910 BitCount = 115 ID = 178
   0.007359 1  246             Rx   d 8 55 01 00 49 50 B6 7A 89  Length = 217925 BitCount = 113 ID = 582
   0.007394 2  86              Rx   d 8 62 00 2A 20 01 84 02 00  Length = 225925 BitCount = 117 ID = 134

读取文件时出错，存储备用行数据

1 个答案: