Question

我想让线程B稍后结束，以便结果总是在结尾显示B9。我怎样才能做到这一点？这是我的代码。

package thread;
import java.lang.*;
import java.lang.Thread;
import java.lang.Runnable;

class Numprintt implements Runnable {
    String myName;
    public Numprintt(String name) {
        myName = name;
    }
    public void run() {
        for(int i = 0; i < 10; i++) {
            System.out.print(myName + i + " ");
        }
    }
}


public class MyRunnableTest {
    public static void main(String[] ar) {

        Numprintt A = new Numprintt("A");
        Numprintt B = new Numprintt("B");

        Thread t1 = new Thread(A);
        Thread t2 = new Thread(B);

        t1.start();
        t2.start();

        try {
            t1.join(); t2.join();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

我的结果可能会显示A1，A2，B1，....，B9 要么， B1，B2，A1，A2，...，A9 我希望结果总是像前一个一样显示。

Answer 1

您可以利用- include_vars: "/etc/ansible/project/{{ some_env }}/vars.yml"的功能。 CountDownLatch使您能够等待从其他线程到同一CountDownLatch对象的倒计时。这是您的问题的基本解决方案。

CountDownLatch

Answer 2

public class MyRunnableTest {
    public static void main(String[] ar) {

    Numprintt A = new Numprintt("A");
    Numprintt B = new Numprintt("B");

    Thread t1 = new Thread(A);
    Thread t2 = new Thread(B);

    t1.start();


    try {
        t1.join(); 
        t2.start();
        t2.join();
    } catch (Exception e) {
        e.printStackTrace();
    }
  }
}

这将保证线程A将首先结束

Java Thread，如何让一个线程始终先停止或结束？

2 个答案: