我有一份作业,我已经到了一个我不知道如何继续的地方。
我遇到了一些问题,但我现在关注的是如何让用户删除ArrayList中的对象。
这就是我的代码。 这是我的主要内容:
import java.util.Scanner;
import java.util.ArrayList;
public class Kennel {
Scanner scan = new Scanner(System.in);
ArrayList<Dog> dogList = new ArrayList<Dog>();
public static void main(String[] args) {
Kennel kenneln = new Kennel();
kenneln.whenStart();
}
public void mainMenu() {
System.out.println("Välj åtgärd: \n" + "[1] Registrera hund \n" + "[2]
Öka
ålder \n" + "[3] Lista svanslängd \n" + "[4] Ta bort hund \n" + "[5]
Avsluta \n" + "Gör ett val: ");
}
public void menuAlt() {
System.out.println();
int menuAlt = scan.nextInt();
switch (menuAlt) {
case 1:
registerDog();
break;
case 2:
increaseAge();
break;
case 3:
listTailLenght();
break;
case 4:
deleteDog();
break;
case 5:
programExit();
break;
default:
System.out.println("Välj en siffra mellan 1 - 5");
whenStart();
}
}
public void registerDog() {
System.out.println("Namn: ");
scan.nextLine();
String name = scan.nextLine();
System.out.print("Ras: ");
String race = scan.nextLine();
System.out.print("Ålder: ");
int age = scan.nextInt();
System.out.print("Vikt: ");
int weight = scan.nextInt();
Dog doggy = new Dog(name, race, age, weight);
dogList.add(doggy);
System.out.println(name + " är nu registrerad!");
}
public void increaseAge() {
System.out.println("Vilken hund har fyllt år? \n" + "Ange namn: ");
int age = scan.nextInt();
}
public void listTailLenght() {
System.out.print("Ange minsta svanslängd: ");
double tailLenght = scan.nextDouble();
System.out.println("Hundar med svanslängd längre än " + tailLenght + ":
");
for (int i = 0; i < dogList.size(); i++) {
if (dogList.get(i).getTailLenght() >= tailLenght) {
System.out.println(dogList.get(i).toString());
}
}
}
public void deleteDog() {
boolean search=true;
while(search) {
System.out.print("Mata in namn på hund som ska tas bort: ");
String searchFor = scan.nextLine();
int ind = dogList.indexOf(searchFor);
if (ind == -1) {
System.out.println("Hund med det namnet fanns ej i registret");
} else {
dogList.remove(ind);
System.out.print("Hunden med det angivna namnet är borttagen ");
}
System.out.print("Fortsätt radera? J/N ?");
String ans = scan.nextLine();
if (!ans.equalsIgnoreCase("J"))
search = false;
}
/*
System.out.println("Mata in namn på hund som ska tas bort: ");
String delete = scan.nextLine();
System.out.println("Hunden med det angivna namnet är borttagen"); }
else
System.out.println("Hund med det namnet fanns ej i registret");
}
*/
}
public void programExit() {
System.out.println("Välkommen åter!");
System.exit(0);
}
public void whenStart() {
while (true) {
mainMenu();
menuAlt();
}
}
}
这是我的狗类:
public class Dog {
private String name;
private String race;
private int age;
private double weight;
private double tailLenght;
public Dog(String name, String race, int age, double weight) {
this.name = name;
this.race = race;
this.age = age;
this.weight = weight;
if (race.equalsIgnoreCase("Tax")) if ´
(race.equalsIgnoreCase("Dachshund")) {
this.tailLenght = 3.7;
} else {
this.tailLenght = (age * weight) / 10;
}
}
public String toString() {
return name + " " + race + " " + age + "år " + weight + " kg " + " svans=" + tailLenght;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getRace() {
return race;
}
public void setRace(String race) {
this.race = race;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public double getWeight() {
return weight;
}
public void setWeight(double weight) {
this.weight = weight;
}
public double getTailLenght() {
return tailLenght;
}
public void setTailLenght(double tailLenght) {
this.tailLenght = tailLenght;
}
}
该程序有5个选项或命令 1.注册狗 2.增加年龄 3.按尾长排序 4.删除狗 5.退出
This is what happens when I try to delete a dog from the ArrayList
为什么程序不允许用户搜索狗,而是直接询问他们是否要删除其他狗?
答案 0 :(得分:5)
您没有覆盖equals
课程的hashcode
和Dog
方法。您将始终通过调用#ArrayList<Dog>.indexOf(String)
返回-1。请参阅JavaDocs indexOf
的工作原理。要解决您的问题,您可以迭代dogList
并比较/搜索String
之类的内容
public void deleteDog() {
...
Iterator<Dog> it = dogList.iterator();
while(it.hasNext()){
Dog dog = it.next();
if(dog.getName().equals(searchFor)){
it.remove();
break;
}
}
...
}
这里需要Iterator
的原因是,因为在循环时你无法使用增强型循环删除项目。