“）此时出人意料。”我做错了什么？

Question

所以，当我运行以下脚本时，我得到了“）此时出乎意料。”因为它击中了第一个“for”声明。

该脚本旨在纠正“数据库”中文件夹的编号结构，数字从最新到最早（从0开始）。 “数据库”中的文件夹结构只需要与以下内容类似地命名：“1 - 2_12_2017”或“34 - 1_14_2017”。

关于我做错了什么的想法？

@echo off
setlocal enabledelayedexpansion
set "dbpth=C:\database"
set cnt=-1
cd %dbpth%
set "fy=unset"
set "fm=unset"
set "fd=unset"
for /f "delims=" %%A in ('dir /b /a:d /o:-n "%dbpth%\*"') do (
    for /f "delims=1234567890-_ " %%B in ("%%A") do (if not "%%B" == "" goto skp)
    set "str=%%A"
    set "str=!str:~-10!"
    set "str=!str: =!"
    set "str=!str:-=!"
        set "ys=unset"
        set "ms=unset"
        set "ds=unset"
    for /f "tokens=1-3 delims=_" %%F in ("!str!") do (
        if !ms! == unset (set "ms=%%F")
        if !ds! == unset (set "ds=%%G")
        if !ys! == unset (set "ys=%%H")
    )
    if !fy! == unset (
        set "fy=!ys!"
        set "fd=!ds!"
        set "fm=!ms!"
    )
    if not !fy! == unset (
        if !ys! leq !fy! (
            set "fy=!ys!"
            if !ms! leq !fm! (
                set "fm=!ms!"
                if !ds! leq !fd! (set "fd=!ds!")
            )
        )
    )
    set /a cnt=!cnt!+1
    :skp
)


:loop
for /f "delims=" %%G in ('dir /b /a:d /o:-n "%dbpth%\*"') do (
    set "str=%%G"
    set "str=!str:~-10!"
    set "str=!str: =!"
    set "str=!str:-=!"
    if !str! == !fm!_!fd!_!fy! (
        ren "%dbpth%\%%G" "!cnt! - !fm!_!fd!_!fy!"
        set /a cnt=!cnt!-1
    )
)
set /a fd=!fd!+1
if !fd! gtr 31 (
    set /a fm=!fm!+1
    set fd=1
    if !fm! gtr 12 (
        set /a fy=!fy!+1
        set fm=1
    )
)
title !cnt! - !fm!_!fd!_!fy!
if !cnt! geq 0 (goto loop)
endlocal
exit