Question

我需要使用WebLogic应用程序服务器10.3.6上安装的ASI建立与Granite数据库的连接。编程语言是Java：

 public void connect() throws Exception {
                 if (prop != null) {
                       ConnectionFactoryASI.setProtocol(prop);
                       ConnectionFactoryASI.setDataObjectFactoryType(prop);
                       serviceFactory = ConnectionFactoryASI.getServiceFactory(prop);
                 } else {
                       serviceFactory = ConnectionFactoryASI.getServiceFactory(user);
                 }
                 dataObjectFactory = serviceFactory.getDataObjectFactory();
                setUser(serviceFactory.getClientSession().getLoginName());
                 logger.debug("ASI HostName: " + serviceFactory.getClientSession().getHostName()
                              + ", DatabaseName: " + serviceFactory.getClientSession().getDatabaseName()
                              + ", DbHostName: " + serviceFactory.getClientSession().getDbHostName());
        }

它没有连接并且给我一个连接错误。

Answer 1

ASI需要一个连接ticketName，没有它就无法打开连接。

这是正确的代码，我添加了上面写的参数：

public void connect(String ticketName) throws Exception {
             if (prop != null) {
                   ConnectionFactoryASI.setProtocol(prop);
                   ConnectionFactoryASI.setDataObjectFactoryType(prop);
                   serviceFactory = ConnectionFactoryASI.getServiceFactory(prop, ticketName);
             } else {
                   serviceFactory = ConnectionFactoryASI.getServiceFactory(ticketName, user);
             }
             dataObjectFactory = serviceFactory.getDataObjectFactory();
            setUser(serviceFactory.getClientSession().getLoginName());
             logger.debug("ASI HostName: " + serviceFactory.getClientSession().getHostName()
                          + ", DatabaseName: " + serviceFactory.getClientSession().getDatabaseName()
                          + ", DbHostName: " + serviceFactory.getClientSession().getDbHostName());
      }

建立与ASI Granite的连接

1 个答案: