在Linux上使用套接字和C创建经过身份验证的JSON-RPC接口请求

时间:2017-12-12 11:59:27

标签: linux sockets curl json-rpc

在我目前的C项目中,我正在尝试使用实现函数来访问需要用户名/密码的json-rpc接口。使用cURL,我成功地使用此命令执行此操作:

curl --user <username>:<password> --data-binary '<json command>' -H 'content-type: text/plain;' <url>

我现在有这个功能:

const char * send_command(const char * command) {
  int sockfd, n;
  struct sockaddr_in serv_addr;
  struct hostent *server;
  char * buffer = malloc(MAXBUFFER);

  sockfd = socket(AF_INET, SOCK_STREAM, 0);
  if (sockfd < 0)
      error("ERROR opening socket");

  server = gethostbyname(URL);
  if (server == NULL) {
      fprintf(stderr,"ERROR, no such host\n");
      exit(0);
  }

  bzero((char *) &serv_addr, sizeof(serv_addr));
  serv_addr.sin_family = AF_INET;
  bcopy((char *)server->h_addr, (char *)&serv_addr.sin_addr.s_addr, server->h_length);
  serv_addr.sin_port = htons(PORT);

  if (connect(sockfd,(struct sockaddr *) &serv_addr,sizeof(serv_addr)) < 0)
      error("ERROR connecting");

  bzero(buffer,MAXBUFFER);
  const char * result = prepare_statement(command);
  strcpy(buffer, result);
  n = write(sockfd,buffer,strlen(buffer));
  if (n < 0)
       error("ERROR writing to socket");

  bzero(buffer,MAXBUFFER);
  n = read(sockfd,buffer,5*MAXBUFFER);
  if (n < 0)
      error("ERROR reading from socket");

  close(sockfd);
  return buffer;
}
如果不需要用户名/密码,

此功能可以起作用。我如何修改此函数以允许对json-rpc接口进行身份验证访问?

0 个答案:

没有答案