Question

处理spring MVC项目以及我从JSP输入的日期是

在Bean类中它是

@DateTimeFormat(pattern = "MM-dd-yyyy") 
        @Temporal(TemporalType.DATE)
        @Column(name="Joining_Date")
        private Date joiningDate; // in jsp as


<td><form:label path="joiningDate">Client Joining Date:</form:label></td>
<td><form:input type="date" path="joiningDate"  value="${client.joiningDate}"/><span id="joiningDateError" ></span></td>

控制器代码

@InitBinder     
public void initBinder(WebDataBinder binder){
     binder.registerCustomEditor(Date.class,     
                         new CustomDateEditor(new SimpleDateFormat("MM-dd-yyyy"), true, 10)); 
}

@RequestMapping(value = "/save", method = RequestMethod.POST)
public ModelAndView saveClient(@ModelAttribute("command") ClientBean clientBean, BindingResult result) {

    System.out.println(clientBean.getJoiningDate());

    if(result.hasErrors()){
        Map<String, Object> model = new HashMap<String, Object>();
        model.put("clients", prepareListofBean(clientService.listClients()));
        return new ModelAndView("addClient", model);
        //return model;
    }

我输入的日期是12/28/2017（MM-dd-yyyy），但输入为0196-01-12

Answer 1

更改

中的日期类型

private Date joiningDate;

到

java.sql.Date

Answer 2

您可以使用它： - 您可以以秒为单位发送时间，然后您可以在jsp侧解析 Java代码应该使用正确的import java.util.Date。

public static String getSimpleDateFormat(long timeInMills) {

    SimpleDateFormat output = new SimpleDateFormat("dd-MMMM-yyyy HH:mm:ss");
    String formattedTime = output.format(timeInMills);

    return formattedTime;
}

use at jsp side :-pass the date 

like var joinDate =formatIntDate(joiningDate);

function formatIntDate(intDate) {

try {
    if (intDate && isInt(intDate))
        return formatDate(new Date(parseInt(intDate)));
    else
        return intDate;
} catch (e) {
    console.log("intDate: " + intDate);
    return intDate;
            }
}

日期格式无法正确保存

2 个答案: