我试图在python和javascript中获得相同的结果但是当加密时我遇到了麻烦，加密在javascript和python中给了我相同的结果但是如果我把数据放在json格式然后加密我得到不同的结果。我可以更改javascript代码，因为对于api，如果需要可以修改python代码。
Python代码：
from datetime import datetime
import json
import hashlib
import hmac
import base64
s="2017-12-11 23:31:55"
data1=dict(timestamp=s)
msg_data = json.dumps(data1)
print msg_data
message = bytes(s).encode('utf-8')
secret = bytes("secret").encode('utf-8')
msg_data2 = bytes(msg_data).encode('utf-8')
signature = base64.b64encode(hmac.new(secret, message, digestmod=hashlib.sha256).digest())
print "without json"
print(signature) #XZqVjDKYG8NRITjiMNXFZnNdUDb+JIr7Vm+f3CabETY=
signature = base64.b64encode(hmac.new(secret, msg_data2, digestmod=hashlib.sha256).digest())
print "with json"
print(signature) #RnxbwptM7HuEE1SPResxc4A6tVDqhv3DxWP75g8pfik=
JS代码：
<script type="text/javascript">
/*
https://raw.githubusercontent.com/jkiss/crypto-js/master/tags/3.1.2/build/rollups/hmac-sha256.js
CryptoJS v3.1.2
code.google.com/p/crypto-js
(c) 2009-2013 by Jeff Mott. All rights reserved.
code.google.com/p/crypto-js/wiki/License
*/
var CryptoJS=CryptoJS||function(h,s){var f={},g=f.lib={},q=function(){},m=g.Base={extend:function(a){q.prototype=this;var c=new q;a&&c.mixIn(a);c.hasOwnProperty("init")||(c.init=function(){c.$super.init.apply(this,arguments)});c.init.prototype=c;c.$super=this;return c},create:function(){var a=this.extend();a.init.apply(a,arguments);return a},init:function(){},mixIn:function(a){for(var c in a)a.hasOwnProperty(c)&&(this[c]=a[c]);a.hasOwnProperty("toString")&&(this.toString=a.toString)},clone:function(){return this.init.prototype.extend(this)}},
r=g.WordArray=m.extend({init:function(a,c){a=this.words=a||[];this.sigBytes=c!=s?c:4*a.length},toString:function(a){return(a||k).stringify(this)},concat:function(a){var c=this.words,d=a.words,b=this.sigBytes;a=a.sigBytes;this.clamp();if(b%4)for(var e=0;e<a;e++)c[b+e>>>2]|=(d[e>>>2]>>>24-8*(e%4)&255)<<24-8*((b+e)%4);else if(65535<d.length)for(e=0;e<a;e+=4)c[b+e>>>2]=d[e>>>2];else c.push.apply(c,d);this.sigBytes+=a;return this},clamp:function(){var a=this.words,c=this.sigBytes;a[c>>>2]&=4294967295<<
32-8*(c%4);a.length=h.ceil(c/4)},clone:function(){var a=m.clone.call(this);a.words=this.words.slice(0);return a},random:function(a){for(var c=[],d=0;d<a;d+=4)c.push(4294967296*h.random()|0);return new r.init(c,a)}}),l=f.enc={},k=l.Hex={stringify:function(a){var c=a.words;a=a.sigBytes;for(var d=[],b=0;b<a;b++){var e=c[b>>>2]>>>24-8*(b%4)&255;d.push((e>>>4).toString(16));d.push((e&15).toString(16))}return d.join("")},parse:function(a){for(var c=a.length,d=[],b=0;b<c;b+=2)d[b>>>3]|=parseInt(a.substr(b,
2),16)<<24-4*(b%8);return new r.init(d,c/2)}},n=l.Latin1={stringify:function(a){var c=a.words;a=a.sigBytes;for(var d=[],b=0;b<a;b++)d.push(String.fromCharCode(c[b>>>2]>>>24-8*(b%4)&255));return d.join("")},parse:function(a){for(var c=a.length,d=[],b=0;b<c;b++)d[b>>>2]|=(a.charCodeAt(b)&255)<<24-8*(b%4);return new r.init(d,c)}},j=l.Utf8={stringify:function(a){try{return decodeURIComponent(escape(n.stringify(a)))}catch(c){throw Error("Malformed UTF-8 data");}},parse:function(a){return n.parse(unescape(encodeURIComponent(a)))}},
u=g.BufferedBlockAlgorithm=m.extend({reset:function(){this._data=new r.init;this._nDataBytes=0},_append:function(a){"string"==typeof a&&(a=j.parse(a));this._data.concat(a);this._nDataBytes+=a.sigBytes},_process:function(a){var c=this._data,d=c.words,b=c.sigBytes,e=this.blockSize,f=b/(4*e),f=a?h.ceil(f):h.max((f|0)-this._minBufferSize,0);a=f*e;b=h.min(4*a,b);if(a){for(var g=0;g<a;g+=e)this._doProcessBlock(d,g);g=d.splice(0,a);c.sigBytes-=b}return new r.init(g,b)},clone:function(){var a=m.clone.call(this);
a._data=this._data.clone();return a},_minBufferSize:0});g.Hasher=u.extend({cfg:m.extend(),init:function(a){this.cfg=this.cfg.extend(a);this.reset()},reset:function(){u.reset.call(this);this._doReset()},update:function(a){this._append(a);this._process();return this},finalize:function(a){a&&this._append(a);return this._doFinalize()},blockSize:16,_createHelper:function(a){return function(c,d){return(new a.init(d)).finalize(c)}},_createHmacHelper:function(a){return function(c,d){return(new t.HMAC.init(a,
d)).finalize(c)}}});var t=f.algo={};return f}(Math);
(function(h){for(var s=CryptoJS,f=s.lib,g=f.WordArray,q=f.Hasher,f=s.algo,m=[],r=[],l=function(a){return 4294967296*(a-(a|0))|0},k=2,n=0;64>n;){var j;a:{j=k;for(var u=h.sqrt(j),t=2;t<=u;t++)if(!(j%t)){j=!1;break a}j=!0}j&&(8>n&&(m[n]=l(h.pow(k,0.5))),r[n]=l(h.pow(k,1/3)),n++);k++}var a=[],f=f.SHA256=q.extend({_doReset:function(){this._hash=new g.init(m.slice(0))},_doProcessBlock:function(c,d){for(var b=this._hash.words,e=b[0],f=b[1],g=b[2],j=b[3],h=b[4],m=b[5],n=b[6],q=b[7],p=0;64>p;p++){if(16>p)a[p]=
c[d+p]|0;else{var k=a[p-15],l=a[p-2];a[p]=((k<<25|k>>>7)^(k<<14|k>>>18)^k>>>3)+a[p-7]+((l<<15|l>>>17)^(l<<13|l>>>19)^l>>>10)+a[p-16]}k=q+((h<<26|h>>>6)^(h<<21|h>>>11)^(h<<7|h>>>25))+(h&m^~h&n)+r[p]+a[p];l=((e<<30|e>>>2)^(e<<19|e>>>13)^(e<<10|e>>>22))+(e&f^e&g^f&g);q=n;n=m;m=h;h=j+k|0;j=g;g=f;f=e;e=k+l|0}b[0]=b[0]+e|0;b[1]=b[1]+f|0;b[2]=b[2]+g|0;b[3]=b[3]+j|0;b[4]=b[4]+h|0;b[5]=b[5]+m|0;b[6]=b[6]+n|0;b[7]=b[7]+q|0},_doFinalize:function(){var a=this._data,d=a.words,b=8*this._nDataBytes,e=8*a.sigBytes;
d[e>>>5]|=128<<24-e%32;d[(e+64>>>9<<4)+14]=h.floor(b/4294967296);d[(e+64>>>9<<4)+15]=b;a.sigBytes=4*d.length;this._process();return this._hash},clone:function(){var a=q.clone.call(this);a._hash=this._hash.clone();return a}});s.SHA256=q._createHelper(f);s.HmacSHA256=q._createHmacHelper(f)})(Math);
(function(){var h=CryptoJS,s=h.enc.Utf8;h.algo.HMAC=h.lib.Base.extend({init:function(f,g){f=this._hasher=new f.init;"string"==typeof g&&(g=s.parse(g));var h=f.blockSize,m=4*h;g.sigBytes>m&&(g=f.finalize(g));g.clamp();for(var r=this._oKey=g.clone(),l=this._iKey=g.clone(),k=r.words,n=l.words,j=0;j<h;j++)k[j]^=1549556828,n[j]^=909522486;r.sigBytes=l.sigBytes=m;this.reset()},reset:function(){var f=this._hasher;f.reset();f.update(this._iKey)},update:function(f){this._hasher.update(f);return this},finalize:function(f){var g=
this._hasher;f=g.finalize(f);g.reset();return g.finalize(this._oKey.clone().concat(f))}})})();
</script>
<script type="text/javascript">
/*
https://raw.githubusercontent.com/jkiss/crypto-js/master/tags/3.1.2/build/components/enc-base64-min.js
CryptoJS v3.1.2
code.google.com/p/crypto-js
(c) 2009-2013 by Jeff Mott. All rights reserved.
code.google.com/p/crypto-js/wiki/License
*/
(function(){var h=CryptoJS,j=h.lib.WordArray;h.enc.Base64={stringify:function(b){var e=b.words,f=b.sigBytes,c=this._map;b.clamp();b=[];for(var a=0;a<f;a+=3)for(var d=(e[a>>>2]>>>24-8*(a%4)&255)<<16|(e[a+1>>>2]>>>24-8*((a+1)%4)&255)<<8|e[a+2>>>2]>>>24-8*((a+2)%4)&255,g=0;4>g&&a+0.75*g<f;g++)b.push(c.charAt(d>>>6*(3-g)&63));if(e=c.charAt(64))for(;b.length%4;)b.push(e);return b.join("")},parse:function(b){var e=b.length,f=this._map,c=f.charAt(64);c&&(c=b.indexOf(c),-1!=c&&(e=c));for(var c=[],a=0,d=0;d<e;d++)if(d%4){var g=f.indexOf(b.charAt(d-1))<<2*(d%4),h=f.indexOf(b.charAt(d))>>>6-2*(d%4);c[a>>>2]|=(g|h)<<24-8*(a%4);a++}return j.create(c,a)},_map:"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="}})();
</script>
<script>
var secret="secret"
data_time= '2017' + '-' + '12' + '-' + '11' + ' ' + '23' + ':' + '31' + ':' + '55';
//params.content['timestamp'] = '2017' + '-' + '12' + '-' + '11' + ' '
// + '23' + ':' + '31' + ':' + '55';
var json = JSON.stringify({"timestamp":"2017-12-11 23:31:55"});
console.log(json);
var data1=CryptoJS.enc.Base64.stringify(CryptoJS.HmacSHA256(data_time,secret));
console.log("Without json:");
console.log(data1);//XZqVjDKYG8NRITjiMNXFZnNdUDb+JIr7Vm+f3CabETY=
var data2=CryptoJS.enc.Base64.stringify(CryptoJS.HmacSHA256(json,secret));
console.log("With json:");
console.log(data2);//s5q78/m3wIb518O8M9x1rAM2DvG/I+Vmt0rBtb6LYS8=
</script>
答案 0 :(得分：3)
program main
!implicit none
include 'mpif.h'
integer cols, divfx, divfy, iter
integer xdiv, ydiv, info, max_iter, x_shift, y_shift
integer, allocatable:: ipiv(:)
double precision, allocatable :: A(:,:), Ainv(:,:)
real, allocatable:: edge(:,:)
double precision, allocatable :: u(:,:), f(:,:)
double precision, allocatable :: u_exact(:,:)
allocatable :: Left(:,:), Right(:,:)
allocatable :: Top(:,:), Bottom(:,:)
allocatable :: TempLeft(:,:), TempRight(:,:)
allocatable :: TempTop(:,:), TempBottom(:,:)
integer myid, master, numprocs, ierr, status(MPI_STATUS_SIZE)
integer i, j, numsent, sender, L, T, R, B
integer anstype, row, dovfx, dovfy, domx, domy, idx
real dom1,dom2,buff
double precision mesh(2), buffer(4), divx, divy, dx, dy, xd, yd
double precision error, derror, error_norm
character(len=100) :: domaindata
call MPI_INIT(ierr)
call MPI_COMM_RANK(MPI_COMM_WORLD, myid, ierr)
call MPI_COMM_SIZE(MPI_COMM_WORLD, numprocs, ierr)
master = 0
divx=0.d0
divy=0.d0
! Input the number of divisions for domain decomposition and calculate sub-domain dimensions.
open(1, file='Inputdata.dat', status='old')
! read(1,*) domx,domy
! read(1,*) dovfx,dovfy
! read(1,*) divfx,divfy
write(*,*)'Starting the Program'
write(*,*) "Enter the number of domain divisions in x-direction &
and y-direction ( Enter 4 if you want three sub-domains)"
read(1,*) domx,domy
write(*,*) domx,domy
write(*,*) "Total number of sub-domains for the problem"
write(*,*) domx*domy
write(*,*) "Enter the sub-domain overlap in x & y -direction as &
a fraction of sub-domain length (multiple of 10)"
read(1,*) dovfx,dovfy
write(*,*) dovfx,dovfy
write(*,*) "Enter the number of divisions in the overlap in &
x & yas a fraction of sub-domain(multiple of 5)"
read(1,*) divfx,divfy
write(*,*) divfx,divfy
divx=1.d0/(((1.d0/domx)/dovfx)/divfx)
divy=1.d0/(((1.d0/domy)/dovfy)/divfy)
write(*,*)"Total number of elemental divisions for the &
problem domain (0,1) in both dimensions"
write(*,*) divx, divy, divx*divy
write(*,*)"Total number of nodal divisions for the problem domain"
write(*,*) (divx+1)*(divy+1)
! time
! **************************
tic = MPI_Wtime();
! Maximum number of iterations.
max_iter=100
! Mesh Size
mesh(1)=1/divx
mesh(2)=1/divy
write(*,*) 'Element Size'
write(*,*) mesh(1), mesh(2)
if ( myid .eq. master ) then
! Send iteration number to subdomain and receive the error from each to
! calculate total error.
write(*,*) 'still1'
do 10 iter = 1,max_iter
do 20 i = 1,domx*domy
call MPI_SEND(iter, 1, MPI_INTEGER, i, i, MPI_COMM_WORLD, ierr)
20 continue
! Receive results obtained from sub-processor/sub-domain
!
error = 0.d0
do 30 i = 1,domx*domy
call MPI_RECV(d_error , 1, MPI_DOUBLE_PRECISION, i, iter, &
MPI_COMM_WORLD, status, ierr)
error = error + d_error
30 continue
write(*,*) 'In iteration ', iter, 'cumulative error is', error*1.d0/domx/domy
10 continue
! time:
! *************
toc = MPI_Wtime();
! Write results to output
! **************************
write(*,*)
write(*,*) 'Time taken for parallel computation is: ',(toc-tic)*1000, 'miliseconds'
else
!************************************ Slaves receive mesh size for discretization ******************************************************
write(*,*) 'iter', iter
write(*,*) 'myid', myid
! Slaves receive corners, then creates a Cartesian grid for finite
! difference until done message received, for one iteration.
! This is done for the first iteration
! Get Domain ID :
if (myid.gt.(domx*domy)) goto 200
write(*,*) 'still31'
1000 call MPI_RECV(iter, 1, MPI_INTEGER, master, MPI_ANY_TAG, MPI_COMM_WORLD, status, ierr)
if (status(MPI_TAG) .eq. 0) goto 200
write(*,*) 'still4'
if (iter.eq.1) then
write(*,*) 'still5'
dom1=domx
dom2=domy
allocate (edge(domx*domy,4))
! Determining the edge matrices for each subdomain - the bounding box
do j =1,domx
do k=1,domy
idx=(j-1)*(domx-1)+k+(j-1)
buff=REAL((mod(idx-1,domx)))/domx
IF (buff-((1.d0/domx)/dovfx) .gt. 0) THEN
buff=buff-((1.d0/domx)/dovfx)
ENDIF
edge(idx,1) = buff
IF ((mod(idx ,domx)) .eq. 0) THEN
buff=1
ELSE
buff=REAL(mod(idx ,domx))/domx
ENDIF
!write(*,*) buff
IF (buff + ((1.d0/domx)/dovfx) .lt. 1) THEN
buff=buff+((1.d0/domx)/dovfx)
ENDIF
edge(idx,2) = buff
!
buff=REAL(floor((idx-1)/dom1))/dom1
IF (buff -((1.d0/domy)/dovfy) .gt. 0) THEN
buff=buff-((1.d0/domy)/dovfy)
ENDIF
edge(idx,3) = buff
buff=REAL(ceiling(idx/dom1))/dom1
IF (buff+((1.d0/domy)/dovfy) .lt. 1) THEN
buff= buff+((1.d0/domy)/dovfy)
ENDIF
edge(idx,4) = buff
end do
end do
write(*,*) myid, edge(myid,:)
write(*,*) 'iter', iter
call Surround_dom(myid,domx,domy,LeftC, RightC, BottomC, TopC)
! Calculate data for the matrices: Divisions in each subdomain. :
xdiv=(edge(myid,2)-edge(myid,1))/mesh(1)
ydiv=(edge(myid,4)-edge(myid,3))/mesh(2)
dx=mesh(1)
dy=mesh(2)
allocate (A((xdiv-1)*(ydiv-1),(xdiv-1)*(ydiv-1)))
allocate (Ainv((xdiv-1)*(ydiv-1),(xdiv-1)*(ydiv-1)))
allocate (u((xdiv-1)*(ydiv-1),1),f((xdiv-1)*(ydiv-1),1))
allocate (u_exact((xdiv-1)*(ydiv-1),1))
allocate (ipiv((xdiv-1)*(ydiv-1)))
allocate (Left((ydiv-1),1),Right((ydiv-1),1))
allocate (Top((xdiv-1),1), Bottom(((xdiv-1)),1))
allocate (TempLeft((ydiv-1),1),TempRight((ydiv-1),1))
allocate (TempTop((xdiv-1),1), TempBottom(((xdiv-1)),1))
Left = 0.d0; Right = 0.d0; Bottom = 0.d0; Top = 0.d0;
TempLeft = 0.d0; TempRight = 0.d0; TempBottom = 0.d0; TempTop = 0.d0;
A=0;
endif
write(*,*) 'still6'
! ******************************************************************
! SendReceive data based on location
! ******************************************************************
if (LeftC.ne.0) then
call MPI_SENDRECV(Left, ydiv - 1, MPI_DOUBLE_PRECISION, LeftC, iter, &
TempLeft, ydiv - 1, MPI_DOUBLE_PRECISION, LeftC, iter, MPI_COMM_WORLD, status, ierr)
end if
if (RightC.ne.0) then
call MPI_SENDRECV(Right, ydiv - 1, MPI_DOUBLE_PRECISION, RightC, iter, &
TempRight, ydiv - 1, MPI_DOUBLE_PRECISION, RightC, iter, MPI_COMM_WORLD, status, ierr)
end if
if (BottomC.ne.0) then
call MPI_SENDRECV(Bottom, xdiv - 1, MPI_DOUBLE_PRECISION, BottomC, iter, &
TempBottom, xdiv - 1, MPI_DOUBLE_PRECISION, BottomC, iter, MPI_COMM_WORLD, status, ierr)
end if
if (TopC.ne.0) then
call MPI_SENDRECV(Top, xdiv - 1, MPI_DOUBLE_PRECISION, TopC, iter, &
TempTop, xdiv - 1, MPI_DOUBLE_PRECISION, TopC, iter, MPI_COMM_WORLD, status, ierr)
end if
Left = TempLeft ;
Right = TempRight;
Top = TempTop ;
Bottom = TempBottom;
write(*,*) 'still7'
! Form the coefficient matrices
do i =1,(xdiv-1)*(ydiv-1)
A(i,i)=-2.d0*(1.d0/(dx**2)+1.d0/(dy**2))
enddo
do i=1,(xdiv-2)
do j=1,(ydiv-1)
A(i+(j-1)*(xdiv-1),i+(j-1)*(xdiv-1)+1)=1.d0/(dx**2)
A(i+(j-1)*(xdiv-1)+1,i+(j-1)*(xdiv-1))=1.d0/(dx**2)
enddo
enddo
do i=1,(xdiv-1)
do j=1,(ydiv-2)
A(i+(j-1)*(xdiv-1),i+(j)*(xdiv-1))=1.d0/(dy**2)
A(i+(j)*(xdiv-1),i+(j-1)*(xdiv-1))=1.d0/(dy**2)
enddo
enddo
write(*,*) 'still9'
L=1
T=1
R=1
B=1
write(*,*) 'still10'
! Impose Boundary Conditions in F matrix
do i=1,(xdiv-1)*(ydiv-1)
xd = edge(myid,1) + (dx)*mod(i,(xdiv-1))
if (mod(i,xdiv-1).eq.0) xd = edge(myid,1) + (dx)*(xdiv-1)
yd = edge(myid,3) + (dy)*ceiling(i*1.d0/(xdiv-1))
!if (iter.eq.1 .and. myid.eq.2) write(*,*) xd,yd
u_exact(i,1) = sin(2.d0*3.1415*xd)*sin(2.d0*3.1415*yd)
f(i,1) = 8.d0*3.1415*3.1415*u_exact(i,1)
IF (mod(i,(xdiv-1)) .eq. 1) THEN
f(i,1)= f(i,1)+Left(L,1)/dx/dx
L=L+1
ENDIF
IF (mod(i,(xdiv-1)) .eq. 0) THEN
f(i,1)=f(i,1)+Right(R,1)/dx/dx
R=R+1
ENDIF
IF (i .le. (xdiv-1)) THEN
f(i,1)=f(i,1)+Bottom(B,1)/dy/dy
B=B+1
ENDIF
IF (i .gt. (xdiv-1)*(ydiv-2)) THEN
f(i,1)=f(i,1)+Top(T,1)/dy/dy
T=T+1
END IF
! enddo
enddo
!Solve AU=F by LU factorization!
write(*,*) 'still11'
do i=1,(xdiv-1)*(ydiv-1)
do j=1,(xdiv-1)*(ydiv-1)
Ainv(i,j)=A(i,j)
end do
end do
! do i=1,(xdiv-1)*(ydiv-1)
! write(*,*) myid,Ainv(i,i)
!end do
call DGESV((xdiv-1)*(ydiv-1), 1, A, &
(xdiv-1)*(ydiv-1), ipiv, f, (xdiv-1)*(ydiv-1), info)
write(*,*) 'still12'
call ErrorNorm(f,u_exact,(xdiv-1)*(ydiv-1),error_norm)
write(*,*) 'still13'
! ****************************************************
! Update boundary conditions based on new solution:
! ****************************************************
x_shift = divfx-1 ;
y_shift = divfy-1 ;
! write(*,*) 'LeftC', myid,LeftC,RightC,TopC,BottomC
if (LeftC.ne.0) then
do 50 i = 1,ydiv - 1
Left(i,1) = f((xdiv - 1)*(i - 1) + 1 + x_shift,1)
!if ((myid.eq.2).and.(iter.eq.1)) write(*,*) 'for left',i, &
!(xdiv - 1)*(i - 1) + 1 + x_shift
50 continue
end if
if (RightC.ne.0) then
do 60 i = 1,ydiv - 1
Right(i,1) = f((xdiv - 1)*i - x_shift,1)
!if ((myid.eq.1).and.(iter.eq.1)) write(*,*) 'for right',i, &
!(xdiv - 1)*i - x_shift
60 continue
end if
if (TopC.ne.0) then
do 70 i = 1,xdiv - 1
Top(i,1) = f((xdiv - 1)*((ydiv - 2) - y_shift) + i,1)
!if ((myid.eq.1).and.(iter.eq.1)) write(*,*) 'for top',i, &
!((xdiv - 1)*((ydiv - 2) - y_shift) + i)
70 continue
end if
if ( BottomC.ne.0) then
do 80 i = 1,xdiv - 1
Bottom(i,1) = f((xdiv - 1)*y_shift + i,1)
!if ((myid.eq.3).and.(iter.eq.1)) write(*,*) 'for bottom',i, &
!((xdiv - 1)*y_shift + i)
80 continue
end if
write(*,*) 'still14'
TempLeft =Left;
TempRight = Right;
TempTop = Top;
TempBottom = Bottom;
call MPI_SEND(error_norm, 1, MPI_DOUBLE_PRECISION, master, iter, &
MPI_COMM_WORLD, ierr)
write(*,*) 'still15'
if (iter.lt.iter_max) go to 1000
! *********************************************************************************
! Write solution to data file to view the results.
! *********************************************************************************
write (domaindata, "(A7,I2,A4)") "domain_",myid,".dat"
open (unit=myid*10, file = domaindata)
write (myid*10,*) ' VARIABLE= "X","Y","U_EXACT","U_CALC" '
do i=1,(xdiv-1)*(ydiv-1)
xd = edge(myid,1) + (dx)*mod(i,(xdiv-1))
if (mod(i,xdiv-1).eq.0) xd = edge(myid,1) + (dx)*(xdiv-1)
yd = edge(myid,3) + (dy)*ceiling(i*1.d0/(xdiv-1))
write (myid*10,*) xd, yd, u_exact(i,1), f(i,1)
enddo
write(*,*) 'still16'
if (iter.eq.max_iter) go to 200
200 continue
write(*,*) 'still45'
endif
call MPI_FINALIZE(ierr)
stop
end program main
subroutine Surround_dom(myid,domx,domy,LeftID, RightID, BottomID, TopID)
implicit none
integer myid, j, k, domy, domx, BottomID, TopID, LeftID, RightID
j = ceiling(1.d0*myid/domx)
k = mod(myid,domx)
if (k.eq.0) k = domx
! Domain on the left
if(k.eq.1) then
LeftID = 0
else
LeftID = ((j-1)*domx + k) - 1
end if
! Domain on the Right
if(k.eq.domx) then
RightID = 0
else
RightID = ((j-1)*domx + k) + 1
end if
! Domain on the Bottom
if(j.eq.1) then
BottomID = 0
else
BottomID = ((j-1)*domx + k) - domx
end if
! Domain on the Top
if(j.eq.domy) then
TopID = 0
else
TopID = ((j-1)*domx + k) + domx
end if
return
end
subroutine ErrorNorm(u,u_exact,N,error_norm)
implicit none
double precision u(N), u_exact(N), err, error_norm
integer i, N
error_norm = 0.d0
do 10 i = 1,N
err = (u(i) - u_exact(i))
error_norm = error_norm + err*err
10 continue
error_norm = sqrt(error_norm)/(N*1.d0)
return
end
和来自javascript的msg_data可能略有不同。
json：
msg_data {"timestamp": "2017-12-11 23:31:55"}
：
json使用可选的separator argument to json.dumps删除每个后面的默认空间：
{"timestamp":"2017-12-11 23:31:55"}
答案 1 :(得分：2)
您正在散列不同的数据。
在Python版本中，msg_data是：
{"timestamp": "2017-12-11 23:31:55"}
^^^
在Javascript版本中，json是：
{"timestamp":"2017-12-11 23:31:55"}
^^
请注意，JS版本中"timestamp":之后没有空格。并非所有JSON实现都会为相同的数据生成完全相同的输出。 （当字典中有多个键时，您会遇到更多问题 - JSON不会对键出现的顺序设置任何要求。）