Question

我有一个object {System.Collections.Generic.List<object>}，里面包含1000 object {DynamicData}，每个{4}包含4个键和值，还有一个List，其中包含2个键和值。我需要将此对象序列化为XML文件，我尝试了正常的序列化，但它给了我这个异常= The type DynamicData was not expected，我如何序列化这个对象？

以下是代码：

           //output is the name of my object
            XmlSerializer xsSubmit = new XmlSerializer(output.GetType());
            var xml = "";

            using (var sww = new StringWriter())
            {
                using (XmlWriter writers = XmlWriter.Create(sww))
                {
                    try
                    {
                        xsSubmit.Serialize(writers, output);
                    }
                    catch (Exception ex)
                    {

                        throw;
                    }
                    xml = sww.ToString(); // Your XML
                }
            }

我可以创建逐行逐行写入的xml文件，但我想要更快更快的代码。我的对象的结构是这样的：

output (count 1000)
 [0]
   Costumer - "Costumername"
   DT - "Date"
   Key - "Key"
   Payment - "x"
   [0]
    Adress - "x"
    Number - "1"
 [1]...
 [2]...

Answer 1

您可以使用IXmlSerializable

实现自己的序列化对象

[Serializable]
public class ObjectSerialize :  IXmlSerializable
{
    public List<object> ObjectList { get; set; }

    public XmlSchema GetSchema()
    {
        return new XmlSchema();
    }

    public void ReadXml(XmlReader reader)
    {

    }

    public void WriteXml(XmlWriter writer)
    {
        foreach (var obj in ObjectList)
        {   
            //Provide elements for object item
            writer.WriteStartElement("Object");
            var properties = obj.GetType().GetProperties();
            foreach (var propertyInfo in properties)
            {   
                //Provide elements for per property
                writer.WriteElementString(propertyInfo.Name, propertyInfo.GetValue(obj).ToString());
            }
            writer.WriteEndElement();
        }
    }
}

<强>用法

        var output = new List<object>
        {
            new { Sample = "Sample" }
        };
        var objectSerialize = new ObjectSerialize
        {
            ObjectList = output
        };
        XmlSerializer xsSubmit = new XmlSerializer(typeof(ObjectSerialize));
        var xml = "";

        using (var sww = new StringWriter())
        {
            using (XmlWriter writers = XmlWriter.Create(sww))
            {
                try
                {
                    xsSubmit.Serialize(writers, objectSerialize);
                }
                catch (Exception ex)
                {

                    throw;
                }
                xml = sww.ToString(); // Your XML
            }
        }

<强>输出

<?xml version="1.0" encoding="utf-16"?>
<ObjectSerialize>
    <Object>
        <Sample>Sample</Sample>
    </Object>
</ObjectSerialize>

注意：如果要使用相同类型反序列化，请注意（ObjectSerialize）你应该提供ReadXml。如果你愿意的话指定架构，您也应该提供GetSchema。

如何将动态对象序列化为xml c＃

1 个答案: