Question

我有这个：

SELECT        ActionDateTime, [Action Location], FirstName, MiddleName, LastName, 
              IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
FROM          dbo.EmployeeEntityTracking AS t
WHERE EXISTS    (SELECT  CAST(ActionDateTime AS DATE) AS Expr1, [Action Location], FirstName, 
                         MiddleName, LastName, IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
                 FROM            dbo.EmployeeEntityTracking AS x
                 WHERE        (IDNumber = t.IDNumber) AND (ActionDateTime <> t.ActionDateTime))

Wich返回带有重复项的记录，但我需要按日期过滤。（查询返回重复但是所有日期。我需要在每个日期重复

Answer 1

尝试使用group by：

SELECT CAST(ActionDateTime AS DATE)
    ,[Action Location]
    ,FirstName
    ,MiddleName
    ,LastName
    ,IDNumber
    ,IDNumber2
    ,IDNumber3
    ,Department
    ,CardData_BadgePass
    ,Location
    ,Birthdate
FROM dbo.EmployeeEntityTracking AS t
GROUP BY
 CAST(ActionDateTime AS DATE)
,[Action Location]
,FirstName
,MiddleName
,LastName
,IDNumber
,IDNumber2
,IDNumber3
,Department
,CardData_BadgePass
,Location
,Birthdate
HAVING COUNT(IDNumber) > 1

PS：它只会显示所有列的重复项，如果只需要ID和日期，请尝试排除所有项目。

Answer 2

首先，没有必要列出exists子句中的所有列，只需用任何固定值替换它们，因为您正在寻找存在不寻找返回列值的行

因为问题不是那么清楚，我根据您可能要求的案例提供了许多建议：

1）如果您希望根据IDNUMBER和ActionDateTime

获得重复项

SELECT * FROM（

SELECT      DISTINCT  ActionDateTime, [Action Location], FirstName, MiddleName, LastName, 
              IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
              ,COUNT(ActionDateTime) OVER(PARTITION BY ActionDateTime,IDNUMBER) AS [ItemCount]
FROM          dbo.EmployeeEntityTracking AS t
WHERE EXISTS    (SELECT         1
                 FROM            dbo.EmployeeEntityTracking AS x
                 WHERE        (x.IDNumber = t.IDNumber) AND (x.ActionDateTime <> t.ActionDateTime))) AS T1
WHERE T1.ItemCount > 1
ORDER BY T1.ActionDateTime

2）如果我理解您要找的内容，您可以使用DISTINCT功能根据所有列消除重复

SELECT      DISTINCT  ActionDateTime, [Action Location], FirstName, MiddleName, LastName, 
              IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
FROM          dbo.EmployeeEntityTracking AS t
WHERE EXISTS    (SELECT         1
                 FROM            dbo.EmployeeEntityTracking AS x
                 WHERE        (x.IDNumber = t.IDNumber) AND (x.ActionDateTime <> t.ActionDateTime))

3）如果您要查找具有相同重复日期的行

SELECT * FROM (

    SELECT      DISTINCT  ActionDateTime, [Action Location], FirstName, MiddleName, LastName, 
                  IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
                  ,COUNT(ActionDateTime) OVER(PARTITION BY ActionDateTime) AS [DateCount]
    FROM          dbo.EmployeeEntityTracking AS t
    WHERE EXISTS    (SELECT         1
                     FROM            dbo.EmployeeEntityTracking AS x
                     WHERE        (x.IDNumber = t.IDNumber) AND (x.ActionDateTime <> t.ActionDateTime))) AS T1
WHERE T1.DateCount > 1
ORDER BY T1.ActionDateTime

4）如果您想要消除包含相同日期的所有行：

SELECT * FROM (

    SELECT      DISTINCT  ActionDateTime, [Action Location], FirstName, MiddleName, LastName, 
                  IDNumber, IDNumber2, IDNumber3, Department, CardData_BadgePass, Location, Birthdate
                  ,COUNT(ActionDateTime) OVER(PARTITION BY ActionDateTime) AS [DateCount]
    FROM          dbo.EmployeeEntityTracking AS t
    WHERE EXISTS    (SELECT         1
                     FROM            dbo.EmployeeEntityTracking AS x
                     WHERE        (x.IDNumber = t.IDNumber) AND (x.ActionDateTime <> t.ActionDateTime))) AS T1
WHERE T1.DateCount < 2
ORDER BY T1.ActionDateTime

SQL选择按日期复制记录

2 个答案: