输入是：
x <- data.frame(
input.number = c(0,1,2,1,1),
input.layer = c(0.0,0.0,0.0,0.0,0.5),
output.number = c(1,1,1,1,1),
output.layer = c(1.0,1.0,1.0,0.5,1.0),
weights = c(-4.9076530,-2.8328544 ,-0.8687123,-2.8328544,-2.8328544)
)
y <- data.frame(
input.number = 2,
input.layer = 0,
output.number = 1,
output.layer = 0.5,
weights = 0
)
通过运行加入它们：
dplyr::full_join(x, y, by = c("input.number", "input.layer", "output.number", "output.layer"), suffix = c('','.dupe'))
结果是一个带有重复列的data.frame：
input.number input.layer output.number output.layer weights weights.dupe
1 0 0.0 1 1.0 -4.9076530 NA
2 1 0.0 1 1.0 -2.8328544 NA
3 2 0.0 1 1.0 -0.8687123 NA
4 1 0.0 1 0.5 -2.8328544 NA
5 1 0.5 1 1.0 -2.8328544 NA
6 2 0.0 1 0.5 NA 0
由于新线不是骗局，我期待这样的事情：
input.number input.layer output.number output.layer weights
1 0 0.0 1 1.0 -4.9076530
2 1 0.0 1 1.0 -2.8328544
3 2 0.0 1 1.0 -0.8687123
4 1 0.0 1 0.5 -2.8328544
5 1 0.5 1 1.0 -2.8328544
6 2 0.0 1 0.5 0
答案 0 :(得分：1)
full_join功能正常。但是，由于bind_rows和x具有相同的列名并且您想要添加“a y，因此dplyr包中的dplyr::bind_rows(x, y)
# input.number input.layer output.number output.layer weights
# 1 0 0.0 1 1.0 -4.9076530
# 2 1 0.0 1 1.0 -2.8328544
# 3 2 0.0 1 1.0 -0.8687123
# 4 1 0.0 1 0.5 -2.8328544
# 5 1 0.5 1 1.0 -2.8328544
# 6 2 0.0 1 0.5 0.0000000
函数似乎正在寻找新行“到数据框。
rbind或者您可以使用基础R中的rbind(x, y)
# input.number input.layer output.number output.layer weights
# 1 0 0.0 1 1.0 -4.9076530
# 2 1 0.0 1 1.0 -2.8328544
# 3 2 0.0 1 1.0 -0.8687123
# 4 1 0.0 1 0.5 -2.8328544
# 5 1 0.5 1 1.0 -2.8328544
# 6 2 0.0 1 0.5 0.0000000
函数。
whereRaw