Question

我想用CSV文件中的数据填充我的json消息。我希望每一行都是一个“新的”json对象。我正在使用Python，并且一旦完成就将代码连接到API。有些数据需要归类为“个人信息”和“carinfo”，我需要在下面的“预期的json消息输出”下的正确类别下填充正确的数据。

这是我到目前为止所做的：

import csv
import json

csvfile = open('test.csv', 'r')
jsonfile = open('file.json', 'w')

fieldnames = ("firstname","r", "lastname","r", "age","r", "gender","r",
              "model","r", "price","r", "loan","r")
reader = csv.DictReader(csvfile, fieldnames)
out = json.dumps( [ row for >row in reader ] )
jsonfile.write(out)

我不知道如何添加两个“个人信息”和“carinfo”类别。

示例csv表：

 FirstName  LastName    Age gender  Car model Price loan
    Anna    Andersson   28  F       Audi    A8 40    FALSE

预期的json消息输出：

{
    "personalinfo": {
        "firstname": "Anna",
        "lastname": "Andersson",
        "age": "28",
        "gender": "F",

        "carinfo": [{
            "car": "Audi",
            "model": "A8"
        }],

        "price": 40,
        "loan": "FALSE"
    }
}

下一条记录应该是一个新的json对象。

Answer 1

您需要将csv文件中的每一行数据转换为按照您描述的方式布局的JSON对象。这可以通过调用单个函数来完成，该函数从csv文件中获取row字典并执行此操作：

import csv
import json

def make_record(row):
    return {
               "personalinfo": {
                   "firstname": row["FirstName"],
                   "lastname": row["LastName"],
                   "age": row["Age"],
                   "gender": row["gender"],

                   "carinfo": [{
                       "car": row["Car"],
                       "model": row["model"]

                   }],
                   "price": row["Price"],
                   "loan": row["loan"]

               }
           }

with open('csv_test.csv', 'r', newline='') as csvfile:
     reader = csv.DictReader(csvfile, delimiter='\t')
     with open('json_file.json', 'w') as jsonfile:
        out = json.dumps([make_record(row) for row in reader])
        jsonfile.write(out)

# show result
with open('json_file.json', 'r') as jsonfile:
    print('results:')
    print(json.dumps(json.load(jsonfile), indent=4))

如何将CSV文件转换为具有嵌套对象的特定JSON格式？

1 个答案: