Spring Rest Controller
@PostMapping(
value = "/post",
produces = MediaType.APPLICATION_JSON_VALUE,
consumes = {MediaType.APPLICATION_JSON_VALUE, MediaType.MULTIPART_FORM_DATA_VALUE}
)
public ResponseEntity<User> handleFileUpload(@RequestParam("user") User user, @RequestPart("file") MultipartFile file) {
// do something with User and file
return ResponseEntity.ok().build();
}
角色服务
@Injectable()
export class UploadFileService {
constructor(private http: HttpClient) { }
pushFileToStorage(file: File): Observable<HttpEvent<{}>> {
let formdata: FormData = new FormData();
formdata.append('file', file);
formdata.append('user', JSON.stringify(new User('John', 12)))
const req = new HttpRequest('POST', '/post', formdata, {
reportProgress: true,
});
return this.http.request(req);
}
}
当我尝试发送请求时,我会 500 Internal Server Error.
这是一个请求标题
POST /post HTTP/1.1
Host: localhost:4200
Connection: keep-alive
Content-Length: 152881
Accept: application/json, text/plain, */*
Content-Type: multipart/form-data; boundary=----WebKitFormBoundarydaQb5yaWw2xu1V9r
Accept-Encoding: gzip, deflate, br
Accept-Language: en-US,en;q=0.9
请求有效负载
------WebKitFormBoundarydaQb5yaWw2xu1V9r
Content-Disposition: form-data; name="file"; filename="Screen Shot 2017-10-24 at 8.49.13 PM.png"
Content-Type: image/png
------WebKitFormBoundarydaQb5yaWw2xu1V9r
Content-Disposition: form-data; name="user"
{"name":"John","age":12}
------WebKitFormBoundarydaQb5yaWw2xu1V9r--
注意:如果在Spring rest控制器中我将参数类型User更改为String,则它可以工作。
问题:如何从Angular发送请求,以便在Spring上我可以获取User和MultipartFile,而不是String。
答案 0 :(得分:1)
更改
public ResponseEntity<User> handleFileUpload(@RequestParam("user") User user, @RequestPart("file") MultipartFile file)
到
public ResponseEntity<User> handleFileUpload(@RequestPart("user") User user, @RequestPart("file") MultipartFile file)
并将请求更改为类似的内容将起作用:
curl -i -X POST -H "Content-Type: multipart/form-data" \
-F 'user={"name":"John","age":12};type=application/json' \
-F "file=@myfile.txt" http://localhost:8080/post
对于consumes
,只需要MediaType.MULTIPART_FORM_DATA_VALUE
。
要以角度形式提出上述类型的请求,可以这样做:
const userBlob = new Blob(JSON.stringify(new User('John', 12)),{ type: "application/json"});
formdata.append('user', userBlob);