Question

    DECLARE @max1 INT;
    DECLARE @max2 INT;
    DECLARE @result INT;
    SELECT @max1= MAX(ISNULL(Table1.Field1,0)) FROM Table1 
    WHERE CAST(Table1.registerDate AS DATE) = CAST (GETDATE() AS DATE)
    SELECT @max2= MAX(ISNULL(Table2.Field1,0)) FROM Table2 
    WHERE CAST(Table2.registerDate AS DATE) = CAST (GETDATE() AS DATE)
    SET @result=CASE WHEN @max1>@max2 THEN @max1+1 ELSE @max2+1 END;

我想根据registerDate从2表中获取最大值并返回此最大值+ 1; 现在最大值为12，此函数返回504例如!! 谁能告诉我这是怎么回事？

更新：根据此代码，一天的第一个值应为1.但在许多情况下，它返回25000例如！

Answer 1

这里没有错。下面的代码按预期返回13。

DECLARE @max1 INT = 12;
DECLARE @max2 INT = 11;
DECLARE @result INT;
--    SELECT @max1= MAX(Table1.Field1) FROM Table1 
--WHERE CAST(Table1.registerDate AS DATE) = CAST (GETDATE() AS DATE)
--    SELECT @max2= MAX(Table2.Field1) FROM Table2 
--WHERE CAST(Table2.registerDate AS DATE) = CAST (GETDATE() AS DATE)

SET @result=CASE WHEN @max1>@max2 THEN @max1+1 ELSE @max2+1 END;
SELECT @result

我打赌下面的一个查询返回的是503。

SELECT  MAX(Table1.Field1) FROM Table1 
WHERE   CAST(Table1.registerDate AS DATE) = CAST (GETDATE() AS DATE)
SELECT  MAX(Table2.Field1) FROM Table2 
WHERE   CAST(Table2.registerDate AS DATE) = CAST (GETDATE() AS DATE)

如何在sql中获取最大值

1 个答案: