Question

我想把时间缩短到即将到来的15分钟时间。例如：

2017-12-11T13:11:51.728Z至2017-12-11T13:15:00.000Z
2017-12-11T13:21:51.728Z至2017-12-11T13:30:00.000Z

Groovy代码：

def currentTime = context.expand('${#Project#currentTime}')
log.info currentTime
date1 =  new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").parse(currentTime)
//Round off the time nearest to the mod 15
Calendar calendar = Calendar.getInstance();
calendar.setTime(date1);
int unroundedMinutes = calendar.get(Calendar.MINUTE);
int mod = unroundedMinutes % 15;
log.info calendar.add(Calendar.MINUTE, mod < 8 ? -mod : (15-mod));

输出

Mon Dec 11 14:32:32 IST 2017：INFO：2017-12-11T14：32：32.690Z
Mon Dec 11 14:32:32 IST 2017：INFO：null

Answer 1

你走了：

为了获得差异分钟，创建了一个闭包。
如果需要，可以递归调用闭包。
如果当前分钟可被15整除，则不会调整时间;这就是在列表中添加第三个值的原因。
为了能够使用多个值进行测试，使用了日期列表。您也可以将它用于单个值。

def timez = ['2017-12-11T13:11:51.728Z', '2017-12-11T13:21:51.728Z', '2017-12-11T13:30:00.000Z']
def dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"
def roundValue = 15
//Change timezone if needed
def tz = 'IST'

TimeZone.setDefault(TimeZone.getTimeZone(tz))

Calendar calendar = Calendar.getInstance()

def getNearestMinutes
//Closure which gets called recursive
getNearestMinutes = { cmin, nearMin = roundValue ->
    def tempResult = cmin % nearMin
    if ( tempResult < nearMin && (0 < (nearMin - cmin)) ) {
        return (nearMin - cmin)
    } else { 
        return getNearestMinutes(cmin, nearMin+roundValue) 
    }
}


//Loop thru times and round the time
timez.each {
    calendar.time = Date.parse(dateFormat,it)
    def currentMinute = calendar.get(Calendar.MINUTE)
    def cof = currentMinute % roundValue
    if (cof) {
        currentMinute += getNearestMinutes(currentMinute)
        calendar.set(Calendar.MINUTE, currentMinute )
    }       
    calendar.set(Calendar.SECOND, 0)
    calendar.set(Calendar.MILLISECOND, 0)
    log.info calendar.time.format(dateFormat)   

}

您可以在线快速尝试 demo

编辑：感觉解决方案可以比在困难条件下应用更简单。

这是另一种解决方案，即将近一段时间到未来15分钟。 然而，与第一个解决方案中的多个条件不同，易于阅读的代码。使用Switch statement

这很简单

def timez = ['2017-12-11T13:11:51.728Z', '2017-12-11T13:21:51.728Z', '2017-12-11T13:30:00.000Z', '2017-12-11T13:46:00.000Z']
def dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"
def roundValue = 15
//Change timezone if needed
def tz = 'IST'

TimeZone.setDefault(TimeZone.getTimeZone(tz))

Calendar calendar = Calendar.getInstance()

def getNexTime = { min ->
  def result
  switch(min) {
    case 1..15: 
        result = 15
        break
    case 16..30:
        result = 30
        break
    case 31..45:
        result = 45
        break
    case 46..60:
        result = 60
        break
    default:
        result = 0
        break
  }
  result
}



//Loop thru times and round the time
timez.each {
    calendar.time = Date.parse(dateFormat,it)
    def currentMinute = calendar.get(Calendar.MINUTE)
    if (0 != getNexTime(currentMinute)) {
        calendar.set(Calendar.MINUTE, getNexTime(currentMinute) )
    }
    calendar.set(Calendar.SECOND, 0)
    calendar.set(Calendar.MILLISECOND, 0)
    println calendar.time.format(dateFormat)    
}

使用Groovy完成即将到来的最近15分钟的时间

1 个答案: