无法在Promise回调中写入socketio?

时间:2017-12-10 22:00:51

标签: javascript socket.io

如果我在该函数之外移动socket.emit,则会发生套接字发出事件。但是,我需要掌握“价值观”。数据,在承诺回电中。在这种情况下,套接字发出事件并不会发生。

app.io.on('connection', function(socket) {
  setInterval(function() {
    var bitfinex = new Promise(
      function(resolve, reject) {
        const orderBook = 'https://api.bitfinex.com/v2/book/tBTCUSD/P0'
        axios.get(orderBook)
          .then(function(response) {
            resolve(response)
          })
          .catch(function(error) {
            reject(error)
          });
      });

    var bitmex = new Promise(
      function(resolve, reject) {
        const orderBook = 'https://www.bitmex.com/api/v1/orderBook/L2?symbol=xbt&depth=25'
        axios.get(orderBook)
          .then(function(response) {
            resolve(response)
          })
          .catch(function(error) {
            reject(error)
          });
      });
    Promise.all([bitmex, bitfinex]).then(values => {
      socket.emit('feed', {
        data: values
      })
    });
  }, 3000)

1 个答案:

答案 0 :(得分:0)

Axios正在返回一个承诺,所以你不需要创建新的Promise,如果有的话你应该抓住你的错误:

app.io.on(
  'connection', 
  function (socket) {
    setInterval(
      function () {
        Promise.all(
          [
            axios.get('https://api.bitfinex.com/v2/book/tBTCUSD/P0'),
            axios.get('https://www.bitmex.com/api/v1/orderBook/L2?symbol=xbt&depth=25')
          ]
        ).then(values =>
          socket.emit(
            'feed',
            {
              data: values
            }
          )
        )
        .catch(
          e => console.warn("something went wrong:",e)
        )
      },
      3000
    )
  }
);