Question

当为了返回字典而调用类时，字典的值是对象在内存中的位置，这不是我需要的。an image of what I am recieving

    class Element:

def __init__(self,name,number,symbol,weight):
    self.__name = name
    self.__number = number
    self.__symbol = symbol
    self.__weight = weight

def getname(self):
    return self.__name   

def getnumber(self):
    return self.__number

def getsymbol(self):
    return self.__symbol

def getweight(self):
    return self.__weight

def __str__(self):
    return self.__name + ' ' + str(self.__number) + ' ' + self.__symbol + ' ' + str(self.__weight)


    class PeriodicTable():

def __init__(self,file):
    lines = open(file,"r").read().split("\n")
    self.ElementsDictionary = {}
    for line in lines[1:]: 
        tokens = line.split(",")
        name, number, symbol, weight = tokens[0], tokens[1], tokens[2], tokens[3]
        self.ElementsDictionary[symbol] = Element(name,number,symbol,weight)

def __str__(self):
    return str(self.ElementsDictionary)

x = PeriodicTable("elements.txt")
print(x)

Answer 1

在这一行中看起来像是一个问题。

self.ElementsDictionary[symbol] = Element(name,number,symbol,weight)

在这里，以字符串格式存储对象，它将解决您的问题

self.ElementsDictionary[symbol] = str(Element(name,number,symbol,weight))

返回内存中对象的位置（python类）

1 个答案: