Question

我希望你能给我一些建议。所以我无法通过RecipeCreateForm将Recipe保存到我的数据库中。

这是我的代码： models.py

class Recipe(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL, related_name='recipes_created')
    title = models.CharField(max_length=200)
    slug = models.SlugField(max_length=200, blank=True)
    image = models.ImageField(upload_to='recipes/%Y/%m/%d')
    description = models.TextField("Description")
    ingredients = models.TextField("Ingredients")
    preparation = models.TextField("Preparation")
    created = models.DateField(auto_now_add=True, db_index=True)

    def __str__(self):
        return self.title

forms.py

from django import forms
from .models import Recipe

class RecipeCreateForm(forms.ModelForm):
    class Meta:
        model = Recipe
        fields = ('title', 'image' 'description', 'ingredients', 'preparation')

Answer 1

您需要在views.py文件中创建一个视图。要创建新对象，视图将如下所示：

comment 99(this is id number)
<div class="dialogbox">
    <div class="body">
        <span class="tip tip-left"></span>
        <div class="message">
            <span id="99">
                <b><a href="/profil/index/1">User Name</a></b>
                <div class="comment">hello world first clck on this. after click on o other edit button. </div>
                <a style="float:right; font-size: 9px;" onclick="return false;" href="" title="">1 day ago</a><br>
                <a href="/posta/index/1">See the post</a> | <a class="edit" id="edit" onclick="return false;">Edit</a> | 
                <a href="/comment/deletecomment/99">Delete</a>
            </span>
        </div>
    </div>
</div>
<br><br>

comment 12 (this is id number)
<div class="dialogbox">
    <div class="body">
        <span class="tip tip-left"></span>
        <div class="message">
            <span id="12">
                <b><a href="/profil/index/1">User Name</a></b>
                <div class="comment">hello world</div>
                <a style="float:right; font-size: 9px;" onclick="return false;" href="" title="">1 day ago</a><br>
                <a href="/posta/index/1">See the post</a> | <a class="edit" id="edit" onclick="return false;">Edit</a> | 
                <a href="/comment/deletecomment/12">Delete</a>
            </span>
        </div>
    </div>
</div>


$(document).on("click", ".edit", function(event) {
    var obje = $(event.target).parent();
    var commentID = obje.attr("id");
    var prev = $(event.target).prev().prev().prev().prev(); 
    comment = prev.html();
    prev.html("<div><textarea class='commentval' style='width: 458px;'>"+comment+"</textarea><button class='save'>save</button></div>");
    $(event.target).removeAttr("class","edit");
    $(event.target).attr("class", "cancel");
    $(event.target).html("Cancel");
});


$(document).on("click", ".cancel", function(event) {
    $(event.target).removeAttr("class","cancel");
    $(event.target).attr("class", "edit");
    $(event.target).html("Edit");
    var prev = $(event.target).prev().prev().prev().prev();
    prev.html(comment);
});

如果请求是post，即您正在将数据从表单保存到数据库。如果请求得到你正在呈现一个空表格。

Answer 2

你错过了一个＆＃39;，＆＃39;在＆＃39;图像＆＃39;之间的形式和＆＃39;描述

这就是为什么错误是＆＃39; imagedescription＆＃39;，它将它们都读作1个字符串。

fields = ('title', 'image' 'description', 'ingredients', 'preparation')

与＆＃39;，＆＃39;它会读

 fields = ('title', 'image', 'description', 'ingredients', 'preparation')

Django添加食谱表格

2 个答案: