Question

到目前为止，我已经学习了JS三个星期，并且在我的一个练习中陷入了某种困境。这是我的代码：

'use strict';

var positions = [
  {
    title: 'Product_Title_1',
    producer: {
      name: 'Producer_Name_1',
      deferPeriod: 10,
      lot: 3
    },
    price: 10000
  },
  {
    title: 'Product_Title_2',
    producer: {
      name: 'Producer_Name_2',
      deferPeriod: 24,
      lot: 14
    },
    price: 9200
  },
  {
    title: 'Product_Title_3',
    producer: {
      name: 'Producer_Name_3',
      deferPeriod: 5,
      lot: 1
    },
    price: 57000
  }
];

console.log('Task 1:');
console.log();


let order = 10; //declaring it here solves the problem in a way, but it is not the way it should work
let shipment;

function lotCalculator (positions, order) {

  return shipment = {
    lots: Math.ceil(order / positions.producer.lot),
    total: Math.ceil(order / positions.producer.lot) * positions.producer.lot * positions.price
  };
}

let result1 = lotCalculator (positions[1], 15);

console.log(result1);

console.log();

console.log(`Order for Product_Title_2: ${order} pcs, order lots: ${shipment.lots}, final cost ${shipment.total} Q`); //order returns undefined

我的代码执行以下操作：它按顺序比较批次的件数;如果订单大小超过订单，则增加订单数量;计算最终费用。

我的问题是：如果不在函数之前声明订单变量，我怎么能让整个事情正常工作？

Answer 1

请勿使用let shipment;代替var shipment;。

您定义的位置let会阻止变量在函数lotCalculator

中使用

JavaScript在console.log中将变量显示为未定义

1 个答案: