我有一个名为temp.json的JSON文件。
{
"users": [
{
"username": "jack",
"email": "jack@somewhere.com",
"total running apps": "1",
"api-mock-app": "0",
"flogo": "1",
"ipaas": "0",
"nodejs-app": "0"
},
{
"username": "jill",
"email": "jill@somewhere.com",
"total running apps": "1",
"api-mock-app": "0",
"flogo": "1",
"ipaas": "0",
"nodejs-app": "0"
}
]
}
我想将此JSON转换为CSV lilke this,
username email total running apps api-mock-app flogo ipaas nodejs-app
jack jack@somewhere.com 1 0 1 0 0
jill jill@somewhere.com 1 0 1 0 0
我试过这个
jq -r '.users[] | keys[0] [.username, .email, ."total running apps", ."api-mock-app", .flogo, .ipaas, ."nodejs-app"] | join(", ") | @csv' temp.json`
但我收到错误
q: error (at temp.json:22): Cannot index string with string "jack"`
任何人都可以解释我在哪里犯了错误,请让我知道正确答案。
答案 0 :(得分:2)
jq 解决方案:
jq -r '(.users[0] | keys_unsorted), (.users[] | to_entries | map(.value))|@csv' temp.json
输出:
"username","email","total running apps","api-mock-app","flogo","ipaas","nodejs-app"
"jack","jack@somewhere.com","1","0","1","0","0"
"jill","jill@somewhere.com","1","0","1","0","0"
答案 1 :(得分:0)
我试过这个,它运作得很好,
jq -r '(.users[0] | keys), (.users[] | [.username, .email, ."total running apps", ."api-mock-app", .flogo, .ipaas, ."nodejs-app"]) | @csv' temp.json
输出格式为。
"api-mock-app","email","flogo","ipaas","nodejs-app","total running apps","username"
"jack","jack@somewhere.com","1","0","1","0","0"
"jill","jill@somewhere.com","1","0","1","0","0"
答案 2 :(得分:0)
我认为最简单的方法是
jq -r "(.users[0] | keys_unsorted), (.users[] | map(.) | @csv)"