Question

我正在尝试使用select语句来查询数据库表中的某些数据。当我输入 =？时查询成功，但当我使用 LIKE％？％时，我在logcat中遇到此错误：

FATAL EXCEPTION: main
Process: com.example.ahmed.bus_time_djerba4, PID: 4178
java.lang.IllegalArgumentException: Cannot bind argument at index 2 because the index is out of range.  The statement has 0 parameters.

这是我调用数据库的方法：

public String  QuerySQL(String DepartStation,String Destination){

    String result="";

    SQLiteDatabase db=this.getReadableDatabase();
    Cursor c=db.rawQuery("select distinct * from "+TABLE_Name+" where "+Col_3+" LIKE '%?%' and "+Col_4+" LIKE '%?%'", new String[]{DepartStation,Destination});

    if(c.getCount()==0) {result="Data not found";c.close();}
    else {
        while (c.moveToNext()) {
            //affichage des lignes
            int ligne = c.getInt(1);
            String Station = c.getString(2);
            String Dest = c.getString(3);
            String hours = c.getString(4);
            result += "\n" + ligne + "|" + Station + "-" + Dest + " " + hours;
        }
        c.close();
    }

    return result;
}

有什么问题？请

Answer 1

问题在于您使用过的SQL查询你在给？准备语句不可接受的字符串。 text2不正确，因为select distinct * from table_name where X like '%?%';将是一个带引号的字符串，例如＆＃39;％＆＃34; your_string＆＃34;％＆＃39;。

代替写：

和select distinct * from table_name where X like ?;使用＆＃34; ?＆＃34;。你也可以将它应用于你的字符串数组。

Answer 2

您应该使用：

Cursor c=db.rawQuery("select distinct * from "+TABLE_Name+" where "+Col_3+" LIKE \"%"+DepartStation+"%\" and "+Col_4+" LIKE \"%"+Destination+"%\"", new String[]{};

代替此：

Cursor c=db.rawQuery("select distinct * from "+TABLE_Name+" where "+Col_3+" LIKE '%?%' and "+Col_4+" LIKE '%?%'", new String[]{DepartStation,Destination});

SQLite：使用rawQuery选择使用LIKE'％？％'

2 个答案: