Question

有人能告诉我为什么这段代码无法使用吗？

list=[5,9,2,5,13] 
item=input("Please enter the search item.")
found=false
for search = 0 to list.length -1
if item==list[search]:
found= True
next search
if found==True:
print("The item is in the list.")
else:
    print("The item is not in the list.")

Answer 1

你至少应该以更好的方式写作，比如：

lst=[5,9,2,5,13] 
item = int(input("Please enter the search item."))
found = False
for search in range(len(lst)):
    if item == (lst[search]):
        found = True
if found:
    print('{} is in the list'.format(item))
else:
    print('{} is not in the list'.format(item))

Answer 2

我不确定语法，如果确实是python。我建议你先查阅一下教程。

但是，您可以在列表中搜索元素：

list=[5,9,2,5,13] 
element = raw_input("Please enter the desired element")

if int(element) in list:  #note i've put int() because your list is made out of numbers rather than strings.
    print element + " is in the list"
else:
    print element + " is not in the list"

Answer 3

这就是你要求的：

value = int(input('Please enter a value to search: '))

if value in [5, 9, 2, 5, 13]:
    print('Item found.')
else:
    print('Item not found.')

如何从列表中搜索项目？

3 个答案: