首先我宣布了
private MediaCapture _mediaCapture;
StorageFile capturedPhoto;
IRandomAccessStream imageStream;
第二我正在捕捉
var lowLagCapture = await _mediaCapture.PrepareLowLagPhotoCaptureAsync(ImageEncodingProperties.CreateUncompressed(MediaPixelFormat.Bgra8));
var capturedPhoto = await lowLagCapture.CaptureAsync();
await lowLagCapture.FinishAsync();
第三我正在设置图像源:
var softwareBitmap = capturedPhoto.Frame.SoftwareBitmap;
SoftwareBitmap softwareBitmapBGRB = SoftwareBitmap.Convert(softwareBitmap, BitmapPixelFormat.Bgra8, BitmapAlphaMode.Premultiplied);
SoftwareBitmapSource bitmapSource = new SoftwareBitmapSource();
await bitmapSource.SetBitmapAsync(softwareBitmapBGRB);
image.Source = bitmapSource;
我怎样才能获得imageStream?我在xaml中使用了CaptureElement工具。
答案 0 :(得分:0)
这很简单,问题是你想用public void HandleImageFileOperations(StorageFile file)
{
if (file != null)
{
//converts the StorageFile to IRandomAccessStream
var stream = await file.OpenAsync(FileAccessMode.Read);
//creates the stream to an Image just in-case you want to show it
var image = new Windows.UI.Xaml.Media.Imaging.BitmapImage();
image.SetSource(stream);
//creates the image into byte array just in-case you need it to store the image
byte[] bitmapImageBytes = null;
var reader = new Windows.Storage.Streams.DataReader(stream.GetInputStreamAt(0));
bitmapImageBytes = new byte[stream.Size];
await reader.LoadAsync((uint)stream.Size);
reader.ReadBytes(bitmapImageBytes);
}
}
做什么。下面是我认为你需要的一些代码:
if (stack.canDoOperation()) {
switch(calculation[i]){
case "*": times(); break;
case "+": sum(); break;
} else {
operationFailed = true;
}