Question

我正在建立一个网络刮板来抓取多个网站，所以我不必直接访问该网站。

目前我遇到了重复网址的问题，该脚本按我的意愿行事，但链接正在重复，我不想要这样做。

这是我的代码：

def HackerNews():
hackerNews = ['https://www.darkreading.com/attacks-breaches.asp','https://www.darkreading.com/application-security.asp',
           'https://www.darkreading.com/vulnerabilities-threats.asp', 'https://www.darkreading.com/endpoint-security.asp',
           'https://www.darkreading.com/IoT.asp','https://www.darkreading.com/vulnerabilities-threats.asp'
           ]
keywords = ["bitcoin", "bit", "BTC", "Bit", "Security","Attack", "Breach","Cyber",
"Ransomware","Botnet","Worm","Hacked","Hack","Hackers","Flaw", "Risk","Danger" ]

for link in hackerNews:
   request = urllib2.Request(link)
   request.add_header('User-Agent', 'Mozilla 5.0')
   websitecontent = urllib2.urlopen(request).read()
   soup = BeautifulSoup(websitecontent, 'html.parser')

   headers = soup.findAll('header', {'class' : 'strong medium'})

   for h in headers:
       a = h.find("a")

       for keyword in keywords:
           if keyword in a["title"]:
               print("Title: " + a["title"] + " \nLink: " "https://darkreading.com" + a["href"])

HackerNews()

这是一个输出示例：

标题：Android Ransomware套件在黑暗网络中崛起链接：https://darkreading.com/mobile/android-ransomware-kits-on-the-rise-in-the-dark-web-/d/d-id/1330591

标题：比特币矿工NiceHash被黑客攻击，可能在比特币上损失了6200万美元链接：https://darkreading.com/cloud/bitcoin-miner-nicehash-hacked-possibly-losing-价值6200万美元的比特币/ d / d-id / 1330585

标题：优步使用$ 100K Bug Bounty付款，沉默佛罗里达黑客：报告链接：https://darkreading.com/attacks-breaches/uber-used- $ 100k-bug-bounty-to-pay-silence-florida-hacker-report / d / d-id / 1330584

Answer 1

好吧，您可以制作包含所有链接的字典，而不是直接打印。或者如果你想把它保存在一个学生列表中。在追加之前，您可以检查它是否已经在列表中。

def HackerNews():
hackerNews = ['https://www.darkreading.com/attacks-breaches.asp','https://www.darkreading.com/application-security.asp',
           'https://www.darkreading.com/vulnerabilities-threats.asp', 'https://www.darkreading.com/endpoint-security.asp',
           'https://www.darkreading.com/IoT.asp','https://www.darkreading.com/vulnerabilities-threats.asp'
           ]
keywords = ["bitcoin", "bit", "BTC", "Bit", "Security","Attack", "Breach","Cyber",
"Ransomware","Botnet","Worm","Hacked","Hack","Hackers","Flaw", "Risk","Danger" ]

output = []

for link in hackerNews:
   request = urllib2.Request(link)
   request.add_header('User-Agent', 'Mozilla 5.0')
   websitecontent = urllib2.urlopen(request).read()
   soup = BeautifulSoup(websitecontent, 'html.parser')

   headers = soup.findAll('header', {'class' : 'strong medium'})

   for h in headers:
       a = h.find("a")

       for keyword in keywords:
           if keyword in a["title"]:
               if (a["title"], a["href"]) not in output:
                   output.append((a["title"], a["href"]))

   for link in output:        
       print("Title: " + link[0] + " \nLink: " "https://darkreading.com" + link[1])

HackerNews()

没有修复你的缩进问题，也没有测试它。但它应该传达我的观点：）

编辑：为python 3工作：

from urllib.request import Request, urlopen
from bs4 import BeautifulSoup


def HackerNews():
    hackerNews = ['https://www.darkreading.com/attacks-breaches.asp','https://www.darkreading.com/application-security.asp',
               'https://www.darkreading.com/vulnerabilities-threats.asp', 'https://www.darkreading.com/endpoint-security.asp',
               'https://www.darkreading.com/IoT.asp','https://www.darkreading.com/vulnerabilities-threats.asp'
               ]
    keywords = ["bitcoin", "bit", "BTC", "Bit", "Security","Attack", "Breach","Cyber",
    "Ransomware","Botnet","Worm","Hacked","Hack","Hackers","Flaw", "Risk","Danger" ]

    output = []

    for link in hackerNews:
       request = Request(link)
       request.add_header('User-Agent', 'Mozilla 5.0')
       websitecontent = urlopen(request).read()
       soup = BeautifulSoup(websitecontent, 'html.parser')

       headers = soup.findAll('header', {'class' : 'strong medium'})

       for h in headers:
           a = h.find("a")

           for keyword in keywords:
               if keyword in a["title"]:
                   if (a["title"], a["href"]) not in output:
                       output.append((a["title"], a["href"]))

       for link in output:
           print("Title: " + link[0] + " \nLink: " "https://darkreading.com" + link[1])

HackerNews()

我为安全新闻构建了一个webscraper，但链接是重复的

1 个答案: