我想创建一个只在满足条件时插入表的触发器。 我尝试过使用IF / BEGIN / END和WHERE的各种组合,但Django每次都会返回一个SQL语法错误。
这里,type_user_id指的是触发类似的人,user_id指的是接收通知的人。它应该只在他们不是同一个人时触发。
a = [1,2]
[a] = [[1,2]]
和
operations = [
migrations.RunSQL(
"DROP TRIGGER like_notification",
"""
CREATE TRIGGER like_notification AFTER INSERT ON user_likes_article
FOR EACH ROW
IF (select user_id from channel WHERE channel_id IN
(SELECT channel_id FROM article WHERE article_id = NEW.article_id)) <> NEW.user_id
BEGIN
INSERT INTO notification (type, type_id, article_id, is_read, type_user_id, user_id)
VALUES ('like', NEW.article_id, NEW.article_id, false, NEW.user_id,
(SELECT user_id from channel WHERE channel_id IN
(SELECT channel_id FROM article WHERE article_id = NEW.article_id)
)
)
END;
"""
)
]
>>>django.db.utils.ProgrammingError: (1064, "You have an error in your SQL syntax;
check the manual that corresponds to your MariaDB server version for the right syntax
to use near 'BEGIN\n INSERT INTO notification (type, type_id, article_id, is_re' at line 5")
和
CREATE TRIGGER like_notification AFTER INSERT ON user_likes_article
FOR EACH ROW
BEGIN
DECLARE @user_same Boolean;
SELECT 1 into @user_same
FROM channel
WHERE channel_id IN (select channel_id FROM article where article_id = NEW.article_id)
AND user_id = NEW.user_id;
IF @user_same <> 1
THEN
INSERT INTO notification (type, type_id, article_id, is_read, type_user_id, user_id,)
VALUES ('like', NEW.article_id, NEW.article_id, false, NEW.user_id, (
SELECT user_id from channel WHERE channel_id IN (
SELECT channel_id FROM article WHERE article_id = NEW.article_id)
)
END IF;
END;
>>>You have an error in your SQL syntax; check the manual that corresponds to your
MariaDB server version for the right syntax to use near '@user_same Boolean;\n SELECT 1 into @user_same\n FRO' at line 4"
我真的不明白为什么它们都不起作用。任何帮助将非常感激!
答案 0 :(得分:0)
@variables
不是DECLARED
。
或者:
DECLARE user_same BOOLEAN;
SELECT 1 INTO user_same WHERE ...
或
SELECT @user_same := 1 WHERE ...
更好的是,这避免了变量的需要。
IF (EXISTS SELECT * FROM ...)
另外,不要使用构造IN ( SELECT ... )
;通常最好使用WHERE EXISTS ( SELECT * FROM ... )
或JOIN ... ON ...
。
(修复后可能会出现更多问题。)
答案 1 :(得分:0)
另一种简便的方法。
您应在;
分隔符之间添加任何符号,以将MySQL语法适当地转换为原始SQL。
CREATE TRIGGER trigger_name BEFORE INSERT ON table
FOR EACH ROW
BEGIN
IF NEW.number <> 'anynumber' AND NEW.number <> 'anynumber'
THEN
SET NEW.number = 'anynumber'; --
END IF; --
END
该示例由于破折号而起作用。