Question

我正在创建一个带字符串的函数并替换＆＃34; put＆＃34;并且＆＃34;得到＆＃34;用＆＃34; xput（）＆＃34;和＆＃34; xget（）＆＃34;。我知道它不是最有效的，但我想从开始工作开始。它目前取代了广告放置括号的字样，但它在每个换行符上都添加括号，我不明白为什么。有人能帮助我吗？

代码：

import re

def replaceFunctions(string):
    split=re.split('(\n)', string)
    for i in range (0,len(split)):
        split[i] = re.split('(")',split[i])

    split = [item for sublist in split for item in sublist]

    for i in range (0,len(split)):
        split[i]=re.split('( )', split[i])

    split = [item for sublist in split for item in sublist]

    for i in range (0,len(split)):
        split[i]=re.split('(\t)', split[i])

    split = [item for sublist in split for item in sublist]
    split.append("\n")

    for i in range (0,len(split)):
        if split[i] == "put":
            split[i] = "xput ("
            for o in range (i,len(split)):
                if split[o] == "\n":
                    split[o] = ")\n"
                    break

        else:
            if split[i] == "get":
                split[i] = "xget ("
                for o in range (i,len(split)):
                    if split[o] == "\n":
                        split[o] = ")\n"
                        break

    string = ""

    for i in range (0,len(split)):
        string += split[i]

    return string

print "get (put)" 
print replaceFunctions("get (put)")

print "put \"put this\"\nput put (get)\n\n\nput\n"
print replaceFunctions("put \"put this\"\nput put (get)\n\n\nput")

输出：

get (put)
xget ( (put))

put "put this"
put put (get)


put

xput ( "xput ( this")
xput ( xput ( (get))
)
)
xput ()

期望的输出：

get (put)
xget ( (put))

put "put this"
put put (get)


put

xput ( "xput ( this")
xput ( xput ( (get))


xput ()

提前致谢！

Answer 1

这会有用吗？

>>> txt = 'this is a text with get, some more get and even a put or two put'
>>> txt.replace('get', 'xget()').replace('put', 'xput()')
'this is a text with xget(), some more xget() and even a xput() or two xput()'

Answer 2

不像@SciGuyMcQ那么紧凑，但更多＆＃34;可扩展＆＃34;：

txt = 'this is a text with get, some more get and even a put or two put'
table = {'get': 'get()',
         'put': 'xput()'}

result = txt[:]
for key in table:
    result = result.replace(key, table[key])

输出：

>>> result
'This is a text with get(), more get() and also xput() and xput() again.'

我的Python函数没有按照需要工作

2 个答案: