Question

我试图在scilab中创建一个简单的GUI，只是为了显示函数a＆＃39; sin（x）的图形，其中滑块正在驱动＆＃34; a＆＃34;的值。我似乎找不到一种方法来只显示对应于＆＃34; a＆＃34; ...的当前值的曲线...它只是将新曲线添加到现有曲线。我希望有一个简单的解决方案，因为我现在无法进一步（我只有Mathematica的经验）。我使用的非常简单的代码是：

// This GUI file is generated by guibuilder version 3.0
//////////
f=figure('figure_position',[400,50],'figure_size',
[656,581],'auto_resize','on','background',[33],'figure_name','Graphic 
window number %d');
//////////
delmenu(f.figure_id,gettext('File'))
delmenu(f.figure_id,gettext('?'))
delmenu(f.figure_id,gettext('Tools'))
toolbar(f.figure_id,'off')
handles.dummy = 0;
handles.slider=uicontrol(f,'unit','normalized','BackgroundColor',
[-1,-1,-1],'Enable','on','FontAngle','normal','FontName','Tahoma',
'FontSize',[12],'FontUnits','points','FontWeight','normal',
'ForegroundColor',[-1,-1,-1],'HorizontalAlignment','left','ListboxTop',
[],'Max',[1],'Min',[0],'Position',[0.0359375,0.78125,0.2625,0.09375],
'Relief','default','SliderStep',
[0.01,0.1],'String','slider1','Style','slider','Value',
[0],'VerticalAlignment','middle','Visible','on','Tag','slider',
'Callback','slider_callback(handles)')
handles.graph= newaxes();handles.graph.margins = [ 0 0 0 
0];handles.graph.axes_bounds = [0.31875,0.01875,0.6640625,0.925];

//////////
// Callbacks are defined as below. Please do not delete the comments as 
it will be used in coming version
//////////

function slider_callback(handles)
//Write your callback for  slider  here
x=0:0.1:10;
a=handles.slider.Value;
plot(x,a*sin(x));
endfunction

提前感谢您的帮助。

Answer 1

默认情况下，每个图形指令都会将其结果添加到当前显示中如果希望在显示新图形指令之前自动擦除图形，可以将轴的自动清除属性设置为“打开”。另一种解决方案是使用删除功能擦除上一个绘图。

如果您不想显示刻度，可以使用xpoly函数代替绘图函数

// This GUI file is generated by guibuilder version 3.0
//////////
f=figure('figure_position',[400,50],'figure_size',...
[656,581],'auto_resize','on','background',[33],'figure_name','Graphic window number %d');
//////////
delmenu(f.figure_id,gettext('File'))
delmenu(f.figure_id,gettext('?'))
delmenu(f.figure_id,gettext('Tools'))
toolbar(f.figure_id,'off')
handles.dummy = 0;
handles.slider=uicontrol(f,'unit','normalized','BackgroundColor',...
[-1,-1,-1],'Enable','on','FontAngle','normal','FontName','Tahoma',...
'FontSize',[12],'FontUnits','points','FontWeight','normal',...
'ForegroundColor',[-1,-1,-1],'HorizontalAlignment','left','ListboxTop',...
[],'Max',[1],'Min',[0],'Position',[0.0359375,0.78125,0.2625,0.09375],...
'Relief','default','SliderStep',...
[0.01,0.1],'String','slider1','Style','slider','Value',...
[0],'VerticalAlignment','middle','Visible','on','Tag','slider',...
'Callback','slider_callback(handles)')
handles.graph= newaxes();
handles.graph.margins = [ 0 0 0 0];
handles.graph.axes_bounds = [0.31875,0.01875,0.6640625,0.925];
handles.graph.data_bounds=[0 -1.2;10 1.2];
handles.graph.auto_clear="on";
//////////
// Callbacks are defined as below. Please do not delete the comments as 
//it will be used in coming version
//////////

function slider_callback(handles)
//Write your callback for  slider  here
x=0:0.1:10;
a=handles.slider.Value;
drawlater()
//delete(handles.graph.children)
xpoly(x,a*sin(x))
handles.graph.data_bounds=[0 -1.2;10 1.2];
drawnow
//plot(x,a*sin(x));
endfunction

Answer 2

您可以访问图形的折线并直接更改数据（x，y）。将空白（或虚拟）图放置在某个地方（例如，靠近uicontrols的定义）。

然后在回调函数中获取当前轴对象：

axes1=gca();// get the current axes

假设您仅绘制了一条线，则折线由axes1.children.children处理（如果您绘制多条线，则它们由axes1.children.children（1），axes1.children.children（2）和等等）。

x和y数据位于折线的“数据”中，因此您只需要更新此数据即可：

axes1.children.children.data=xymatrix([x1,y1;x2,y2;x3,y3;...xn,yn]);

您的回调函数可能如下所示：

function slider_callback(handles)
//Write your callback for  slider  here
x=zeros(101,2);//define matrix with 101 rows and 2 columns
x(:,1)=0:0.1:10;//fill first column with x axis values
a=handles.slider.Value;//get slider value
x(:,2)=a*sin(x(:,1));//fill second column with y axis values
axes1=gca();//get current axes
axes1.children.children.data=x;//update polyline data with new xy data
endfunction

Scilab - gui - 在调整滑块期间自动调整图形...？

2 个答案: