我试图用CSV处理时间序列数据并计算时间纪元数,本例中epoch = 1000毫秒
这是python代码:
import csv
import os
import datetime
eeg_record = []
path = "C:\\Users\\ary\\Desktop\\nuerosky blink tests\\backup\\process_from_backup\\blink_50px\\task_blink40000radious50px_duration_40000.csv"
"""read CSV file"""
def get_dirs(path_):
if os.access(path_,os.F_OK and os.R_OK):
f = open(path_)
row_counter = 0
for row in csv.reader(f):
##print(row)
##skip the header
if row_counter == 0:
row_counter = row_counter + 1
continue
else:
eeg_record.append(row)
f.close()
"""get the number of epochs based on a epoch size in milliseconds"""
def get_number_of_epochs(epoch_size_in_milliseconds):
initial_datetime = datetime.datetime(2000,1,1,0,0,0,0)
current_datetime = datetime.datetime(2000,1,1,0,0,0,0)
epoch_counter = 0
row_counter = 0
epoch = datetime.timedelta(milliseconds=epoch_size_in_milliseconds)
for row in eeg_record:
if row_counter == 0:
row_counter = row_counter + 1
initial_datetime = str_to_datetime_(row[1])
else:
current_datetime = str_to_datetime_(row[1])
if initial_datetime - current_datetime >= epoch:
initial_datetime = current_datetime
epoch_counter = epoch_counter + 1
print("counter: ",epoch_counter)
""" covert datetime of this format 2017-10-13 19:22:50:525 to datetime object"""
def str_to_datetime_(datetime_str):
return datetime.datetime(datetime_str,'%Y-%m-%d %H:%M:%S:%f')
我通过Spyder IDE和Python 3.6.2运行它
我的意见
get_number_of_epochs(1000)
数据示例:
Time_Stamp_In_Milli_Secs,Time_Stamp_Formatted,Raw,A,B,C,D,Class_Stimulia
1.50795E+12,2017-10-13 19:22:13:249,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:249,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:253,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:253,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:268,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:268,53,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA
错误:
文件“”,第33行,在get_number_of_epochs中 initial_datetime = str_to_datetime_(row [1])
文件“”,第45行,在str_to_datetime_中 return datetime.datetime(datetime_str,'%Y-%m-%d%H:%M:%S:%f')
TypeError:需要一个整数(得到str类型)
如何使用代码中的当前API修复此错误?
由于
答案 0 :(得分:2)
执行以下操作并查看:
将 str_to_datetime _ 功能更改为以下
def str_to_datetime_(datetime_str):
return datetime.datetime.strptime(datetime_str, '%Y-%m-%d %H:%M:%S:%f')
答案 1 :(得分:0)
我认为你在寻找的是
datetime.datetime.strptime(datetime_str, '%Y-%m-%d %H:%M:%S:%f')
标准datetime
构造函数看起来像
datetime.datetime(year: int, month: int, day: int, hour: int, minute: int, second: int, millisecond: int, tzinfo: datetime.tzinfo)