Question

我有一个字典定义的类型如下：

variables.yml
---
fileName1:
  dict1:
    prop1:
     key: "key"
     value: "value"
    prop2:
     key:"key"
     value: "value"
    prop3:
    ..and so on
  dict2:
    prop1:
     key:"key"
     value: "value"
    prop2:
     key: "key"
     value: "value"
  dict3:

fileName2:
 ...and similar structure follows for fileName 2,3, 4.

在我的ansible任务中，我想要迭代我正在做的事情：

- name: invlude variable file
  include_vars: variables.yml

- name: iterate over the dict and sub dict
  debug: msg="{{ item.value }}"
  with_dict: "{{ var[filename] }}"
  when: item.key == "dict1"

这里的输出给我的值为prop1：... prop2：... prop3：..依此类推。我需要进一步迭代像我尝试使用

的prop *

- name: iterate over the dict and sub dict
  debug: msg="{{ item.value.item }}"
  with_dict: "{{ var[filename] }}"
  when: item.key == "dict1"

但是因为dict没有任何元素作为项目返回错误。我需要对此进行泛型迭代。任何帮助将不胜感激。

Answer 1

必须有一种更简单的方法来做到这一点，但我画了一个空白，这种方式可以迭代道具：

testvars.yml：

---

fileName1:
  dict1:
    prop1:
     key: "key111"
     value: "value111"
    prop2:
     key: "key112"
     value: "value112"
    prop3:
     key: "key113"
     value: "value113"
  dict2:
    prop1:
     key: "key121"
     value: "value121"
    prop2:
     key: "key123"
     value: "value122"

fileName2:
  dict1:
    prop1:
     key: "key211"
     value: "value211"
    prop2:
     key: "key212"
     value: "value212"
    prop3:
     key: "key213"
     value: "value213"
  dict2:
    prop1:
     key: "key221"
     value: "value221"
    prop2:
     key: "key222"
     value: "value222"

test.yml：

---

- hosts: 127.0.0.1
  gather_facts: no
  tasks:
  - include_vars: testvars.yml

  - name: Iterate
    include_tasks: test2.yml
    vars:
      loopitem: "{{ item.value }}"
    with_dict: "{{ fileName1 }}"
    when: item.key == 'dict1'

test2.yml

---

- debug:
    msg: "Property {{prop.key}} has the keypair {{prop.value.key}} : {{prop.value.value}}"
  with_dict: "{{ loopitem }}"
  loop_control:
    loop_var: prop

我需要以通用的方式用ansible迭代字典

1 个答案: