Question

我尝试使用一个button创建自定义对话框（ TRY AGAIN ）这个对话框测试是否有互联网连接。当用户点击（ TRY AGAIN ）按钮并且如果没有互联网连接时，将再次显示自定义对话框，并且当有互联网连接对话框时将被解除

 private void showDialog() {
        myDialog = new Dialog(getActivity());
        myDialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
        assert myDialog.getWindow() != null;
        myDialog.getWindow().setBackgroundDrawable(new ColorDrawable(Color.TRANSPARENT));
        myDialog.setContentView(R.layout.alert_dialog);
        text.setText(getResources().getText(R.string.nointernent));
        myDialog.setCancelable(false);
        Button tyragain = myDialog.findViewById(R.id.tryagainbtn);
        tyragain.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
              if (!isNetworkConnected()) {
                    showDialog();
                }
                else{
                    myDialog.dismiss();

                }
            }
        });

        myDialog.show();
}

/ ** /

public  boolean isNetworkConnected() {
    ConnectivityManager connectionManager = (ConnectivityManager) getActivity().getApplicationContext().getSystemService(Context.CONNECTIVITY_SERVICE);
    if (connectionManager == null) {
        return false;
    }
    NetworkInfo networkInfo = connectionManager.getActiveNetworkInfo();
    if (networkInfo == null) {
        return false;
    }
    return networkInfo.isConnected();
}

Answer 1

最后我通过添加myDialog.isShowing()

解决了我的问题

if (!isNetworkConnected() && myDialog.isShowing()) {
                    showDialog();

                }
                else{
                    myDialog.dismiss();
                    refreshContent();
                }

我无法解除自定义对话框

1 个答案: