Question

您好我需要读取文件并从文件到结构数组获取数据。

结构

struct Activity {
    string ID;
    string Name;
    string quantity; };

我有这个从文件中读取的功能

int* fillStructure(ifstream &fileActivity){


    int i=0;
    int numberOfElements = numberOfLines(fileActivity);

    Activity* myActivity = new Activity[numberOfElements];

    while (i < numberOfElements)
    {
          getline(fileActivity, myAktivity[i].ID, ',');
          getline(fileActivity, myActivity[i].Name, ',');
          getline(fileActivity, myActivity[i].quantity, '\n');      
          i++;
    }

   fileActivity.close(); 
   return myActivity; }

当我尝试在main函数中打印结构成员时它不起作用

int main(){



    if (!(fileActivity.is_open())){
        cout << "Error when reading file" << endl;
        return 0;
    }  

    fillStructure(fileActivity);

    cout << myActivity[1].ID << endl; return 0;  }

我是初学者，你能帮我解决我做错的事吗？

Answer 1

您在myActivity中声明了void fillStructure(ifstream &fileActivity)，但尝试从int main()进行访问。

Answer 2

您必须在main函数中声明返回值。

# From Paul Eggert (2014-09-06):
# Monthly Notices of the Royal Astronomical Society 44, 4 (1884-02-08), 208
# says that New York City Hall time was 3 minutes 58.4 seconds fast of
# Eastern time (i.e., -4:56:01.6) just before the 1883 switch.  Round to the
# nearest second.

在 main 函数中声明 fillStructure 函数的返回类型，如下所示：

Zone America/New_York   -4:56:02 -  LMT 1883 Nov 18 12:03:58

此代码段适用于我

C ++从文件填充结构数组

2 个答案: