如何解析高级Json数据

Question

我有一个JSON输出，如下所示。我使用getjson来获取数据。我的目标是将datetime和value字段（斜体和粗体）视为[16:35:08,30.579 kbit/s],[16:35:38,23.345 kbit/s]。有没有办法成功呢？谢谢，

{
    "prtg-version": "17.3.33.2830",
    "treesize": 4,
    "histdata": [{
        "***datetime***": "04.12.2017 16:35:08",
        "datetime_raw": 43073.5660648727,
        "value": "111.983 KByte",
        "value_raw": 114670936.0000,
        "***value***": "30.579 kbit/s",
        "value_raw": 3822364.5333,
        "value": "107.893 KByte",
        "value_raw": 110482503.0000,
        "value": "29.462 kbit/s",
        "value_raw": 3682750.1000,
        "value": "4.090 KByte",
        "value_raw": 4188433.0000,
        "value": "1.117 kbit/s",
        "value_raw": 139614.4333,
        "coverage": "100 %",
        "coverage_raw": 10000
    }, {
        "***datetime***": "04.12.2017 16:35:38",
        "datetime_raw": 43073.5664120718,
        "value": "85.464 KByte",
        "value_raw": 87514907.0000,
        "***value***": "23.345 kbit/s",
        "value_raw": 2918136.2788,
        "value": "81.993 KByte",
        "value_raw": 83960378.0000,
        "value": "22.397 kbit/s",
        "value_raw": 2799612.4708,
        "value": "3.471 KByte",
        "value_raw": 3554529.0000,
        "value": "948 kbit/s",
        "value_raw": 118523.8079,
        "coverage": "100 %",
        "coverage_raw": 10000
    }]
}

Answer 1

只需将数组映射到函数中，然后根据需要解析值。

以下示例使用：

• Array.map循环遍历数组
• String.split使用空格分割字符串并仅获取最后一部分
• Template literals public static string GetBusDate(bool mtdIndicator, bool prev2BusDtInd) { string busDate = Helper.PreviousBusinessDate; if (mtdIndicator) { busDate = Helper.FOMBusDt; } else if (prev2BusDtInd) { busDate = Helper.Previous2BusinessDate; } return busDate; } 输出值

相关方法：

``

检查代码段：

＆＃13;

＆＃13;

const result = data.histdata.map(hist => {
  const datetime = hist['***datetime***'].split(' ')[1];
  const value = hist['***value***'];
  return `${datetime},${value}`;
});

＆＃13;

＆＃13;

＆＃13;