XML Restrict基于另一个元素值

Question

基本上我有我的XML版本1.0，我有一个复杂的元素，有以下示例：

var time = new ol.layer.Group({ ....... });

let intervalHandle = null;
let activeLayerIndex = -1;

function startAnimation() {
  // check if interval is already running
  if (!intervalHandle) {
    activeLayerIndex = 0;
    // make sure all layers of the group are hidden
    time.getLayers().forEach(layer => layer.setVisible(false));

    intervalHandle = setInterval(function() {
      const allLayers = time.getLayers();
      if (activeLayerIndex >= allLayers.getLength()) {
        // we reached the end, stop animating
        stopAnimation();
      }
      allLayers.item(activeLayerIndex).setVisible(true);

      if (activeLayerIndex > 0) {
        // hide the previous layer
        allLayers.item(activeLayerIndex -1).setVisible(false);
      }
      activeLayerIndex += 1;
    }, 500 /* milliseconds */);
  }
}

function stopAnimation() {
  if(intervalHandle) {
    clearInterval(intervalHandle);
    intervalHandle = null;
  }
}

我在XML Schema中定义了以下内容：

<tile>
  <position>5</position>
  <type>floor</type>
  <towerPlacement>true</towerPlacement>
</tile>

有没有办法让我的<xs:element name="type"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="road"/> <xs:enumeration value="floor"/> <xs:enumeration value="startPos"/> <xs:enumeration value="endPos"/> </xs:restriction> </xs:simpleType> </xs:element> 成为towerPlacement？

type = floor

Answer 1

XSD 1.0

您的约束无法在XSD 1.0中表示。

XSD 1.1

您的约束可以在XSD 1.1中表达，使用断言声明towerPlacement true type = 'floor'只有<?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:vc="http://www.w3.org/2007/XMLSchema-versioning" vc:minVersion="1.1"> <xs:element name="tile"> <xs:complexType> <xs:sequence> <xs:element name="position" type="xs:integer"/> <xs:element name="type"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="road"/> <xs:enumeration value="floor"/> <xs:enumeration value="startPos"/> <xs:enumeration value="endPos"/> </xs:restriction> </xs:simpleType> </xs:element> <xs:element name="towerPlacement" type="xs:string"/> </xs:sequence> <xs:assert test="(type='floor' and towerPlacement='true') or towerPlacement!='true'"/> </xs:complexType> </xs:element> </xs:schema> ：

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